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Selenium Pythontesting~10 mins

Find element by CSS selector in Selenium Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to find an element by its CSS selector.

Selenium Python
element = driver.find_element_by_css_selector([1])
Drag options to blanks, or click blank then click option'
A"#submit-button"
B"submit button"
C".submit-button"
D"submit-button"
Attempts:
3 left
💡 Hint
Common Mistakes
Forgetting to add '#' before the id in the selector.
Using a class selector '.' instead of id selector '#'.
2fill in blank
medium

Complete the code to find an element with class 'menu-item' using CSS selector.

Selenium Python
element = driver.find_element_by_css_selector([1])
Drag options to blanks, or click blank then click option'
A"menu item"
B"#menu-item"
C"menu-item"
D".menu-item"
Attempts:
3 left
💡 Hint
Common Mistakes
Using the class name without '.' prefix.
Using '#' which is for id selectors.
3fill in blank
hard

Fix the error in the code to find an element by CSS selector for a button with class 'btn-primary'.

Selenium Python
element = driver.find_element_by_css_selector([1])
Drag options to blanks, or click blank then click option'
A".btn-primary"
B"btn-primary"
C"#btn-primary"
D"button.btn-primary"
Attempts:
3 left
💡 Hint
Common Mistakes
Using the class name without '.' prefix.
Using id selector '#' instead of class selector '.'
4fill in blank
hard

Fill both blanks to find an input element with type 'text' using CSS selector.

Selenium Python
element = driver.find_element_by_css_selector("input[[1]='[2]']")
Drag options to blanks, or click blank then click option'
Atype
Btext
Cusername
Dname
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping attribute name and value.
Using 'name' instead of 'type' for the first blank.
5fill in blank
hard

Fill all three blanks to find a button element with class 'btn' and text 'Submit' using CSS selector.

Selenium Python
element = driver.find_element_by_css_selector("button.[1]:contains('[2]')")  # Note: :contains is not standard CSS
# Alternative: find by class and then check text separately
button = driver.find_element_by_css_selector("button.[3]")
Drag options to blanks, or click blank then click option'
Abtn
BSubmit
Dsubmit
Attempts:
3 left
💡 Hint
Common Mistakes
Using incorrect class name without '.' prefix.
Trying to use :contains which is not supported in Selenium CSS selectors.

Practice

(1/5)
1. Which method is used in Selenium Python to find an element by CSS selector?
easy
A. driver.find_element_by_name("selector")
B. driver.find_element(By.CSS_SELECTOR, "selector")
C. driver.find_element_by_xpath("selector")
D. driver.find_element_by_id("selector")

Solution

  1. Step 1: Understand Selenium element finding methods

    Selenium provides different methods to find elements, including by ID, name, XPath, and CSS selector.
  2. Step 2: Identify the correct method for CSS selector

    The method to find by CSS selector is driver.find_element(By.CSS_SELECTOR, "selector").
  3. Final Answer:

    driver.find_element(By.CSS_SELECTOR, "selector") -> Option B
  4. Quick Check:

    Find element by CSS selector = driver.find_element(By.CSS_SELECTOR, "selector") [OK]
Hint: Use By.CSS_SELECTOR with find_element for CSS selectors [OK]
Common Mistakes:
  • Using find_element_by_id for CSS selectors
  • Confusing XPath with CSS selector method
  • Using deprecated find_element_by_* methods
2. Which of the following is the correct syntax to find an element with class name "btn-primary" using CSS selector in Selenium Python?
easy
A. driver.find_element(By.CSS_SELECTOR, ".btn-primary")
B. driver.find_element(By.CSS_SELECTOR, "#btn-primary")
C. driver.find_element(By.CSS_SELECTOR, "btn-primary")
D. driver.find_element(By.CSS_SELECTOR, "*btn-primary")

Solution

  1. Step 1: Recall CSS selector for class names

    In CSS selectors, a class is selected by prefixing the class name with a dot (.)
  2. Step 2: Match the correct syntax

    To select class "btn-primary", use ".btn-primary" inside find_element.
  3. Final Answer:

    driver.find_element(By.CSS_SELECTOR, ".btn-primary") -> Option A
  4. Quick Check:

    Class selector = .classname [OK]
Hint: Use dot (.) before class name in CSS selector [OK]
Common Mistakes:
  • Using # instead of . for class selectors
  • Omitting the dot before class name
  • Using invalid wildcard * before class name
3. What will the following Selenium Python code select?
element = driver.find_element(By.CSS_SELECTOR, "div#main > ul.items > li.active")
medium
A. The first <li> element with class 'active' inside <ul> with class 'items' inside <div> with id 'main'
B. All <li> elements inside any <ul> inside any <div>
C. The <div> element with id 'main' only
D. The <ul> element with class 'items' only

Solution

  1. Step 1: Break down the CSS selector

    The selector targets a
  2. element with class 'active' that is a direct child of a <ul> with class 'items', which is a direct child of a <div> with id 'main'.
  3. Step 2: Understand the element selected

    It selects the first matching
  4. element with class 'active' inside the specified structure.
  5. Final Answer:

    The first <li> element with class 'active' inside <ul> with class 'items' inside <div> with id 'main' -> Option A
  6. Quick Check:

    CSS selector matches nested elements exactly [OK]
Hint: Read CSS selector from right to left for nested elements [OK]
Common Mistakes:
  • Thinking it selects all <li> elements, not just with class 'active'
  • Ignoring the direct child (>) combinators
  • Confusing id (#) and class (.) selectors
4. Identify the error in this Selenium Python code snippet:
element = driver.find_element(By.CSS_SELECTOR, "#content .item[active]")
medium
A. The ID selector #content should be a class selector
B. The method find_element does not accept CSS selectors
C. The CSS selector should use double quotes inside single quotes
D. The attribute selector [active] is missing an equals sign and value

Solution

  1. Step 1: Analyze the attribute selector syntax

    The selector uses [active] which means attribute 'active' must be present, but usually attributes require a value like [active="true"].
  2. Step 2: Identify the correct attribute selector format

    To check for attribute presence only, [active] is valid, but if a value is expected, it must be [active="value"]. Here, likely a value is missing.
  3. Final Answer:

    The attribute selector [active] is missing an equals sign and value -> Option D
  4. Quick Check:

    Attribute selectors need correct syntax [OK]
Hint: Attribute selectors need = and value unless checking presence only [OK]
Common Mistakes:
  • Assuming [active] always works without value
  • Confusing ID (#) and class (.) selectors
  • Using wrong quotes inside CSS selector string
5. You want to find all <input> elements inside a form with id "loginForm" that have both classes "input-field" and "required". Which CSS selector should you use with Selenium Python's find_elements method?
hard
A. "form#loginForm input#input-field#required"
B. "form#loginForm input .input-field .required"
C. "form#loginForm input.input-field.required"
D. "form#loginForm > input > .input-field > .required"

Solution

  1. Step 1: Understand CSS selector for multiple classes

    To select elements with multiple classes, chain class selectors without spaces, e.g., .input-field.required.
  2. Step 2: Combine with tag and parent selectors

    Use form#loginForm to select the form by id, then space to select descendants, then input.input-field.required for inputs with both classes.
  3. Final Answer:

    "form#loginForm input.input-field.required" -> Option C
  4. Quick Check:

    Multiple classes chained without spaces [OK]
Hint: Chain multiple classes without spaces in CSS selector [OK]
Common Mistakes:
  • Adding spaces between multiple classes (selects descendants instead)
  • Using multiple IDs on one element (invalid)
  • Using child combinator (>) incorrectly for nested elements
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10 questions~5 mineasy hard