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Selenium Pythontesting~10 mins

CSS attribute selectors in Selenium Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to select an element with attribute type equal to submit using CSS selector.

Selenium Python
element = driver.find_element(By.CSS_SELECTOR, "input[[1]='submit']")
Drag options to blanks, or click blank then click option'
Atype
Bclass
Cid
Dname
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'class' or 'id' instead of 'type' in the selector.
Forgetting the quotes around the attribute value.
2fill in blank
medium

Complete the code to select all elements whose data-test attribute contains the word button.

Selenium Python
elements = driver.find_elements(By.CSS_SELECTOR, "[data-test[1]='button']")
Drag options to blanks, or click blank then click option'
A^
B~
C|
D*
Attempts:
3 left
💡 Hint
Common Mistakes
Using '*=' which matches substring anywhere, not whole words.
Using '=' which matches exact value only.
3fill in blank
hard

Fix the error in the CSS selector to select elements with href attribute starting with https.

Selenium Python
link = driver.find_element(By.CSS_SELECTOR, "a[[1]^='https']")
Drag options to blanks, or click blank then click option'
Aclass
Bsrc
Chref
Did
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'src' or 'class' instead of 'href'.
Using '=' instead of '^=' operator.
4fill in blank
hard

Fill both blanks to select elements with title attribute ending with .pdf and containing download anywhere in the attribute value.

Selenium Python
elements = driver.find_elements(By.CSS_SELECTOR, "[[1]$='.pdf'][[2]*='download']")
Drag options to blanks, or click blank then click option'
Atitle
Bhref
Dclass
Attempts:
3 left
💡 Hint
Common Mistakes
Using different attributes for the two selectors.
Mixing up $= and *= operators.
5fill in blank
hard

Fill all three blanks to create a dictionary comprehension that maps each data-id attribute value to the text of elements whose class attribute contains active.

Selenium Python
result = { [1]: element.text for element in driver.find_elements(By.CSS_SELECTOR, "[class[2]='active']") if element.get_attribute([3]) is not None }
Drag options to blanks, or click blank then click option'
Aelement.get_attribute('data-id')
B'class'
C'data-id'
D*=
Attempts:
3 left
💡 Hint
Common Mistakes
Using '=' instead of '*=' in the CSS selector.
Using wrong attribute names in get_attribute or selector.

Practice

(1/5)
1. What does the CSS selector input[type='text'] select in Selenium?
easy
A. All input elements regardless of type
B. All elements with any attribute containing 'text'
C. All elements with class 'text'
D. All input elements with type attribute exactly equal to 'text'

Solution

  1. Step 1: Understand the attribute selector syntax

    The selector input[type='text'] targets input tags with an attribute type exactly equal to 'text'.
  2. Step 2: Match the selector meaning to options

    All input elements with type attribute exactly equal to 'text' correctly describes this exact match. Other options describe different or incorrect matches.
  3. Final Answer:

    All input elements with type attribute exactly equal to 'text' -> Option D
  4. Quick Check:

    Exact attribute match = C [OK]
Hint: Exact match uses [attr='value'] syntax [OK]
Common Mistakes:
  • Confusing exact match with partial match
  • Selecting wrong tag type
  • Mixing class selectors with attribute selectors
2. Which of the following is the correct CSS selector to find elements with an attribute data-id that starts with 'user'?
easy
A. [data-id^='user']
B. [data-id*='user']
C. [data-id$='user']
D. [data-id='user']

Solution

  1. Step 1: Recall CSS attribute selectors for matching start of value

    The caret symbol ^= means 'starts with' in CSS attribute selectors.
  2. Step 2: Match the selector to the question

    [data-id^='user'] uses [data-id^='user'], which selects elements whose data-id attribute starts with 'user'.
  3. Final Answer:

    [data-id^='user'] -> Option A
  4. Quick Check:

    Starts with selector = B [OK]
Hint: Use ^= for 'starts with' attribute matching [OK]
Common Mistakes:
  • Using *= instead of ^= for starts with
  • Using $= which means ends with
  • Using exact match = instead of partial
3. What will the following Selenium Python code print if the page has three <input> elements with name attributes: 'user1', 'user2', and 'admin'?
elements = driver.find_elements(By.CSS_SELECTOR, "input[name*='user']")
print(len(elements))
medium
A. 2
B. 3
C. 1
D. 0

Solution

  1. Step 1: Understand the CSS selector input[name*='user']

    This selector finds input elements whose name attribute contains the substring 'user'.
  2. Step 2: Count matching elements

    Given names 'user1', 'user2', and 'admin', only 'user1' and 'user2' contain 'user'. So, 2 elements match.
  3. Final Answer:

    2 -> Option A
  4. Quick Check:

    Substring match count = 2 [OK]
Hint: Use *= to find attributes containing substring [OK]
Common Mistakes:
  • Counting all inputs instead of filtered ones
  • Confusing starts with (^) and contains (*) selectors
  • Assuming exact match instead of partial
4. You wrote this Selenium code but it throws an error:
element = driver.find_element(By.CSS_SELECTOR, "button[class^='submit']'")
What is the error and how to fix it?
medium
A. Wrong attribute selector; use *= instead of ^=
B. Extra single quote at the end; remove it to fix
C. Missing tag name before attribute selector
D. CSS selector cannot use ^ for attribute matching

Solution

  1. Step 1: Inspect the CSS selector string syntax

    The selector ends with an extra single quote after the closing double quote: "button[class^='submit']'". This causes a syntax error.
  2. Step 2: Correct the string by removing the extra quote

    Removing the extra single quote at the end fixes the syntax: "button[class^='submit']".
  3. Final Answer:

    Extra single quote at the end; remove it to fix -> Option B
  4. Quick Check:

    Check quotes balance = A [OK]
Hint: Check for balanced quotes in selectors [OK]
Common Mistakes:
  • Ignoring syntax errors caused by quotes
  • Changing correct attribute selectors unnecessarily
  • Assuming CSS does not support ^= selector
5. You want to select all <a> tags whose href attribute ends with '.pdf' or '.docx' using a single CSS selector in Selenium. Which selector is correct?
hard
A. a[href*='.pdf' or '.docx']
B. a[href$='.pdf' || href$='.docx']
C. a[href$='.pdf'], a[href$='.docx']
D. a[href$='.pdf'][href$='.docx']

Solution

  1. Step 1: Understand CSS selector for multiple attribute matches

    To select elements matching either condition, use a comma to separate selectors: a[href$='.pdf'], a[href$='.docx'].
  2. Step 2: Analyze other options for correctness

    a[href$='.pdf' || href$='.docx'] uses invalid syntax with || inside attribute selector. a[href$='.pdf'][href$='.docx'] requires both endings simultaneously, impossible. a[href*='.pdf' or '.docx'] uses invalid syntax with 'or'.
  3. Final Answer:

    a[href$='.pdf'], a[href$='.docx'] -> Option C
  4. Quick Check:

    Use comma to combine selectors = D [OK]
Hint: Combine selectors with comma for OR conditions [OK]
Common Mistakes:
  • Using logical operators inside attribute selectors
  • Trying to combine multiple attribute endings in one selector without comma
  • Assuming multiple attribute selectors mean OR instead of AND
Recommended

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10 questions~5 mineasy hard