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Selenium Javatesting~20 mins

Executing JavaScript in Selenium Java - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
JavaScript Execution Master
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Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
What is the output of this JavaScript execution in Selenium?
Consider the following Selenium Java code snippet that executes JavaScript to get the page title. What will be the value of pageTitle after execution?
Selenium Java
JavascriptExecutor js = (JavascriptExecutor) driver;
String pageTitle = (String) js.executeScript("return document.title;");
A"" (empty string)
BThe current page's title as a String
Cnull
DThrows a ClassCastException
Attempts:
2 left
💡 Hint
Remember that executeScript returns an Object that you can cast to the expected type.
❓ assertion
intermediate
2:00remaining
Which assertion correctly verifies JavaScript execution result?
You execute JavaScript to get the number of links on a page. Which assertion correctly checks that the number is 10?
Selenium Java
JavascriptExecutor js = (JavascriptExecutor) driver;
Long linkCount = (Long) js.executeScript("return document.getElementsByTagName('a').length;");
AassertEquals(10, linkCount);
BassertTrue(linkCount == 10);
CassertEquals(10L, linkCount);
DassertEquals("10", linkCount);
Attempts:
2 left
💡 Hint
Check the type returned by executeScript for numeric values.
🔧 Debug
advanced
2:00remaining
Why does this JavaScript execution throw an exception?
This Selenium Java code throws a ClassCastException. What is the cause?
Selenium Java
JavascriptExecutor js = (JavascriptExecutor) driver;
String result = (String) js.executeScript("return 5 + 5;");
AexecuteScript returns a Long for numeric results, not a String
BThe JavaScript syntax is invalid
CCasting to String is always safe here
DexecuteScript cannot return primitive values
Attempts:
2 left
💡 Hint
Check the Java type returned for JavaScript numeric results.
🧠 Conceptual
advanced
2:00remaining
What is the best way to scroll to an element using JavaScript in Selenium?
You want to scroll the page so a specific WebElement is visible. Which JavaScript snippet executed via Selenium is best?
Selenium Java
JavascriptExecutor js = (JavascriptExecutor) driver;
WebElement element = driver.findElement(By.id("myElement"));
Ajs.executeScript("element.scrollIntoView();");
Bjs.executeScript("window.scrollTo(0, 1000);");
Cjs.executeScript("document.body.scrollTop = 1000;");
Djs.executeScript("arguments[0].scrollIntoView();", element);
Attempts:
2 left
💡 Hint
Use arguments to pass WebElement safely to JavaScript.
❓ framework
expert
3:00remaining
How to safely execute asynchronous JavaScript and get result in Selenium Java?
You want to execute asynchronous JavaScript that calls a callback when done. Which Selenium method and approach is correct?
AUse executeAsyncScript and call arguments[arguments.length - 1]() in JS when done
BUse executeScript and wait manually for result
CUse executeScript and return a Promise from JS
DUse executeAsyncScript but do not call the callback in JS
Attempts:
2 left
💡 Hint
Asynchronous JS requires a callback to signal completion.

Practice

(1/5)
1. What is the main purpose of using JavascriptExecutor in Selenium Java?
easy
A. To locate elements on the page using JavaScript selectors
B. To execute JavaScript code directly in the browser during a test
C. To start the Selenium WebDriver session
D. To generate test reports automatically

Solution

  1. Step 1: Understand the role of JavascriptExecutor

    JavascriptExecutor allows running JavaScript code inside the browser from Selenium tests.
  2. Step 2: Identify the main use case

    It is mainly used to perform actions or retrieve information that Selenium WebDriver cannot do directly.
  3. Final Answer:

    To execute JavaScript code directly in the browser during a test -> Option B
  4. Quick Check:

    JavascriptExecutor runs JS code in browser [OK]
Hint: Remember: JavascriptExecutor runs JS code inside browser [OK]
Common Mistakes:
  • Confusing JavascriptExecutor with element locators
  • Thinking it starts WebDriver sessions
  • Assuming it generates reports
2. Which of the following is the correct way to cast a WebDriver instance to JavascriptExecutor in Selenium Java?
easy
A. JavascriptExecutor js = driver.executeScript();
B. JavascriptExecutor js = driver.getJavascriptExecutor();
C. JavascriptExecutor js = new JavascriptExecutor(driver);
D. JavascriptExecutor js = (JavascriptExecutor) driver;

Solution

  1. Step 1: Recall the casting syntax in Java

    To use JavascriptExecutor, you cast the WebDriver instance like this: (JavascriptExecutor) driver.
  2. Step 2: Check each option

    JavascriptExecutor js = (JavascriptExecutor) driver; uses correct casting syntax. The other options are invalid method calls or constructors.
  3. Final Answer:

    JavascriptExecutor js = (JavascriptExecutor) driver; -> Option D
  4. Quick Check:

    Cast driver to JavascriptExecutor using (JavascriptExecutor) [OK]
Hint: Casting uses (JavascriptExecutor) before driver [OK]
Common Mistakes:
  • Using non-existent methods like getJavascriptExecutor()
  • Trying to instantiate JavascriptExecutor with new keyword
  • Calling executeScript() without casting
3. What will be the output of the following code snippet?
JavascriptExecutor js = (JavascriptExecutor) driver;
String title = (String) js.executeScript("return document.title;");
System.out.println(title);
medium
A. Prints the current page's title
B. Throws a ClassCastException
C. Prints 'undefined'
D. Prints the URL of the page

Solution

  1. Step 1: Understand the JavaScript executed

    The script returns document.title, which is the page's title as a string.
  2. Step 2: Check the casting and output

    The returned object is cast to String and printed, so it outputs the page title.
  3. Final Answer:

    Prints the current page's title -> Option A
  4. Quick Check:

    executeScript returns document.title string [OK]
Hint: executeScript returns JS value; cast to String for title [OK]
Common Mistakes:
  • Expecting URL instead of title
  • Not casting return value to String
  • Confusing output with undefined or errors
4. Identify the error in the following code snippet:
JavascriptExecutor js = (JavascriptExecutor) driver;
js.executeScript("arguments[0].click();");
medium
A. Incorrect casting of driver to JavascriptExecutor
B. executeScript method does not exist
C. Missing WebElement argument to click()
D. JavaScript syntax error in the string

Solution

  1. Step 1: Analyze the executeScript call

    The script uses arguments[0].click(); which requires a WebElement passed as an argument.
  2. Step 2: Check the method call parameters

    No WebElement is passed to executeScript, so it will fail at runtime.
  3. Final Answer:

    Missing WebElement argument to click() -> Option C
  4. Quick Check:

    arguments[0] needs a WebElement passed [OK]
Hint: Pass WebElement as argument when using arguments[0] [OK]
Common Mistakes:
  • Forgetting to pass WebElement argument
  • Assuming casting is wrong
  • Thinking executeScript method is missing
5. You want to scroll a page to a specific WebElement using JavaScript in Selenium Java. Which code snippet correctly achieves this?
hard
A. js.executeScript("arguments[0].scrollIntoView(true);", element);
B. js.executeScript("window.scrollTo(element);");
C. js.executeScript("scrollToElement(arguments[0]);", element);
D. js.executeScript("document.scrollTo(arguments[0]);");

Solution

  1. Step 1: Recall JavaScript method to scroll to element

    The correct JS method is scrollIntoView(true) called on the element.
  2. Step 2: Check the Selenium executeScript usage

    Pass the WebElement as an argument and use arguments[0].scrollIntoView(true); to scroll.
  3. Final Answer:

    js.executeScript("arguments[0].scrollIntoView(true);", element); -> Option A
  4. Quick Check:

    Use scrollIntoView with element argument [OK]
Hint: Use arguments[0].scrollIntoView(true) with element [OK]
Common Mistakes:
  • Using window.scrollTo with element (invalid)
  • Calling non-existent scrollToElement function
  • Not passing element as argument
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10 questions~5 mineasy hard