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Selenium Javatesting~10 mins

Creating new windows/tabs in Selenium Java - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to open a new browser tab using Selenium WebDriver.

Selenium Java
driver.switchTo().newWindow([1]);
Drag options to blanks, or click blank then click option'
AWindowType.POPUP
BWindowType.WINDOW
CWindowType.TAB
DWindowType.FRAME
Attempts:
3 left
💡 Hint
Common Mistakes
Using WindowType.WINDOW opens a new window, not a tab.
Using WindowType.FRAME or WindowType.POPUP are invalid for this method.
2fill in blank
medium

Complete the code to switch the WebDriver context to the newly opened tab.

Selenium Java
String newTabHandle = driver.getWindowHandles().toArray()[[1]].toString();
driver.switchTo().window(newTabHandle);
Drag options to blanks, or click blank then click option'
A1
B0
C2
D-1
Attempts:
3 left
💡 Hint
Common Mistakes
Using index 0 switches back to the original window.
Using negative or out-of-range indices causes errors.
3fill in blank
hard

Fix the error in the code to correctly open a new window instead of a tab.

Selenium Java
driver.switchTo().newWindow([1]);
Drag options to blanks, or click blank then click option'
AWindowType.WINDOW
BWindowType.FRAME
CWindowType.TAB
DWindowType.POPUP
Attempts:
3 left
💡 Hint
Common Mistakes
Using WindowType.TAB opens a new tab, not a window.
WindowType.POPUP and WindowType.FRAME are invalid here.
4fill in blank
hard

Fill both blanks to open a new tab and navigate to a URL.

Selenium Java
driver.switchTo().newWindow([1]);
driver.get([2]);
Drag options to blanks, or click blank then click option'
AWindowType.TAB
B"https://example.com"
C"https://selenium.dev"
DWindowType.WINDOW
Attempts:
3 left
💡 Hint
Common Mistakes
Using WindowType.WINDOW opens a new window, not a tab.
Passing a variable instead of a string URL causes errors.
5fill in blank
hard

Fill all three blanks to open a new window, switch to it, and verify the title.

Selenium Java
driver.switchTo().newWindow([1]);
String newHandle = driver.getWindowHandles().toArray()[[2]].toString();
driver.switchTo().window(newHandle);
assertEquals([3], driver.getTitle());
Drag options to blanks, or click blank then click option'
AWindowType.WINDOW
B1
C"New Window Title"
DWindowType.TAB
Attempts:
3 left
💡 Hint
Common Mistakes
Using WindowType.TAB opens a tab, not a window.
Using wrong index for window handles causes switching errors.
Passing a variable instead of a string literal to assertEquals.

Practice

(1/5)
1. Which Selenium Java command is used to open a new browser tab?
easy
A. driver.switchTo().newWindow(WindowType.TAB)
B. driver.openNewTab()
C. driver.createTab()
D. driver.newWindow(Tab)

Solution

  1. Step 1: Understand Selenium's new window/tab creation

    Selenium provides a method driver.switchTo().newWindow() to open new tabs or windows.
  2. Step 2: Identify the correct WindowType for a tab

    Using WindowType.TAB opens a new tab, which matches driver.switchTo().newWindow(WindowType.TAB).
  3. Final Answer:

    driver.switchTo().newWindow(WindowType.TAB) -> Option A
  4. Quick Check:

    Open new tab = driver.switchTo().newWindow(WindowType.TAB) [OK]
Hint: Use driver.switchTo().newWindow(WindowType.TAB) for new tabs [OK]
Common Mistakes:
  • Using non-existent methods like driver.openNewTab()
  • Confusing WindowType.WINDOW with TAB
  • Trying to create tabs without switchTo()
2. Which of the following is the correct syntax to open a new browser window in Selenium Java?
easy
A. driver.newWindow(WindowType.WINDOW);
B. driver.switchTo().newWindow(WindowType.WINDOW);
C. driver.switchTo().openWindow(WindowType.WINDOW);
D. driver.openNewWindow(WindowType.WINDOW);

Solution

  1. Step 1: Recall the correct method to open new windows

    The correct method is driver.switchTo().newWindow() with a WindowType argument.
  2. Step 2: Match the exact syntax

    driver.switchTo().newWindow(WindowType.WINDOW); matches the correct syntax exactly with WindowType.WINDOW.
  3. Final Answer:

    driver.switchTo().newWindow(WindowType.WINDOW); -> Option B
  4. Quick Check:

    Open new window = driver.switchTo().newWindow(WindowType.WINDOW) [OK]
Hint: Use switchTo().newWindow(WindowType.WINDOW) to open new windows [OK]
Common Mistakes:
  • Omitting switchTo() before newWindow()
  • Using incorrect method names like openWindow()
  • Missing semicolon in Java syntax
3. What will be the output of the following Selenium Java code snippet?
driver.get("https://example.com");
String originalHandle = driver.getWindowHandle();
driver.switchTo().newWindow(WindowType.TAB);
driver.get("https://selenium.dev");
System.out.println(driver.getCurrentUrl());
driver.switchTo().window(originalHandle);
System.out.println(driver.getCurrentUrl());
medium
A. https://selenium.dev https://selenium.dev
B. https://example.com https://selenium.dev
C. https://selenium.dev https://example.com
D. https://example.com https://example.com

Solution

  1. Step 1: Understand window handles and tab switching

    The code opens example.com, saves the original window handle, then opens a new tab and navigates to selenium.dev.
  2. Step 2: Analyze the printed URLs

    First print shows the URL of the new tab (selenium.dev). Then it switches back to the original window and prints its URL (example.com).
  3. Final Answer:

    https://selenium.dev https://example.com -> Option C
  4. Quick Check:

    Switch tabs = different URLs printed [OK]
Hint: Switching tabs changes current URL output [OK]
Common Mistakes:
  • Assuming URLs remain the same after switching tabs
  • Not saving original window handle before opening new tab
  • Confusing getWindowHandle() with getWindowHandles()
4. Identify the error in the following Selenium Java code snippet that tries to open a new tab:
driver.get("https://example.com");
driver.newWindow(WindowType.TAB);
driver.get("https://selenium.dev");
medium
A. No error, code is correct
B. WindowType.TAB is invalid
C. driver.get() cannot be used after newWindow()
D. Missing driver.switchTo() before newWindow()

Solution

  1. Step 1: Check method usage for opening new tabs

    The method newWindow() must be called after driver.switchTo().
  2. Step 2: Identify the missing part in the code

    The code calls driver.newWindow() directly, which is incorrect syntax.
  3. Final Answer:

    Missing driver.switchTo() before newWindow() -> Option D
  4. Quick Check:

    Always use switchTo().newWindow() [OK]
Hint: Always use driver.switchTo() before newWindow() [OK]
Common Mistakes:
  • Calling newWindow() directly on driver
  • Confusing WindowType.TAB as invalid
  • Thinking driver.get() is restricted after newWindow()
5. You want to open a new tab, navigate to a URL, then switch back to the original tab and verify its title. Which code snippet correctly does this in Selenium Java?
hard
A. String original = driver.getWindowHandle(); driver.switchTo().newWindow(WindowType.TAB); driver.get("https://selenium.dev"); driver.switchTo().window(original); assert driver.getTitle().contains("Example");
B. driver.switchTo().newWindow(WindowType.TAB); driver.get("https://selenium.dev"); String original = driver.getWindowHandle(); driver.switchTo().window(original); assert driver.getTitle().contains("Example");
C. String original = driver.getWindowHandle(); driver.newWindow(WindowType.TAB); driver.get("https://selenium.dev"); driver.switchTo().window(original); assert driver.getTitle().contains("Example");
D. driver.get("https://selenium.dev"); driver.switchTo().newWindow(WindowType.TAB); driver.switchTo().window(original); assert driver.getTitle().contains("Example");

Solution

  1. Step 1: Save original window handle before opening new tab

    We must save the original window handle before opening a new tab to switch back later.
  2. Step 2: Open new tab, navigate, then switch back and assert title

    String original = driver.getWindowHandle(); driver.switchTo().newWindow(WindowType.TAB); driver.get("https://selenium.dev"); driver.switchTo().window(original); assert driver.getTitle().contains("Example"); correctly calls switchTo().newWindow(WindowType.TAB), navigates, switches back using saved handle, and asserts title.
  3. Final Answer:

    Option A code snippet correctly performs all steps -> Option A
  4. Quick Check:

    Save handle, open tab, switch back, assert [OK]
Hint: Save handle before new tab, switch back to assert [OK]
Common Mistakes:
  • Saving window handle after opening new tab
  • Calling newWindow() without switchTo()
  • Not switching back before assertion
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10 questions~5 mineasy hard