Bird
0
0

Given the following Selenium Java code snippet, what will be printed?

medium📝 Predict Output Q4 of 15
Selenium Java - Handling Windows, Frames, and Alerts
Given the following Selenium Java code snippet, what will be printed?
String firstHandle = driver.getWindowHandle();
driver.switchTo().newWindow(WindowType.TAB);
String secondHandle = driver.getWindowHandle();
System.out.println(firstHandle == secondHandle);
ACompilation error
Btrue
Cnull
Dfalse
Step-by-Step Solution
Solution:
  1. Step 1: Understand getWindowHandle()

    This returns the current window handle as a String.
  2. Step 2: After newWindow(WindowType.TAB)

    The driver switches to a new tab, so getWindowHandle() returns a different handle.
  3. Step 3: Comparing handles with ==

    Since these are different String objects representing different windows, the comparison returns false.
  4. Final Answer:

    false -> Option D
  5. Quick Check:

    Different tabs have different handles [OK]
Quick Trick: New tabs have distinct handles; comparing them returns false [OK]
Common Mistakes:
MISTAKES
  • Assuming handles are equal after opening new tab
  • Using == instead of equals() for String comparison
  • Expecting true because of same driver instance

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