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Selenium Javatesting~10 mins

Element screenshots in Selenium Java - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to take a screenshot of a web element.

Selenium Java
WebElement element = driver.findElement(By.id("logo"));
File screenshot = element.[1]();
Drag options to blanks, or click blank then click option'
AsaveScreenshot
BtakeScreenshot
CcaptureScreenshot
DgetScreenshotAs
Attempts:
3 left
💡 Hint
Common Mistakes
Using takeScreenshot() which does not exist.
Using captureScreenshot() which is not a Selenium method.
2fill in blank
medium

Complete the code to specify the output type for the screenshot.

Selenium Java
File screenshot = element.getScreenshotAs([1].FILE);
Drag options to blanks, or click blank then click option'
AOutputType
BScreenshotType
CFileType
DImageType
Attempts:
3 left
💡 Hint
Common Mistakes
Using ScreenshotType which is not a Selenium class.
Using FileType which does not exist in Selenium.
3fill in blank
hard

Fix the error in the code to save the element screenshot to a file.

Selenium Java
File screenshot = element.getScreenshotAs(OutputType.FILE);
FileUtils.[1](screenshot, new File("element.png"));
Drag options to blanks, or click blank then click option'
AwriteFile
BcopyFile
CsaveFile
DmoveFile
Attempts:
3 left
💡 Hint
Common Mistakes
Using saveFile() which does not exist.
Using writeFile() which is not a FileUtils method.
4fill in blank
hard

Fill both blanks to capture and save a screenshot of an element with id 'submit'.

Selenium Java
WebElement submitButton = driver.findElement(By.[1]("submit"));
File screenshot = submitButton.getScreenshotAs(OutputType.[2]);
Drag options to blanks, or click blank then click option'
Aid
Bname
CFILE
DBASE64
Attempts:
3 left
💡 Hint
Common Mistakes
Using By.name instead of By.id for locating by id.
Using OutputType.BASE64 which returns a string, not a file.
5fill in blank
hard

Fill all three blanks to capture an element screenshot and save it as 'button.png'.

Selenium Java
WebElement button = driver.findElement(By.[1]("button"));
File screenshot = button.getScreenshotAs(OutputType.[2]);
FileUtils.[3](screenshot, new File("button.png"));
Drag options to blanks, or click blank then click option'
AcssSelector
BFILE
CcopyFile
Dxpath
Attempts:
3 left
💡 Hint
Common Mistakes
Using cssSelector instead of xpath for locating.
Using OutputType.BASE64 instead of FILE.
Using FileUtils.moveFile instead of copyFile.

Practice

(1/5)
1. What is the main purpose of taking an element screenshot in Selenium Java?
easy
A. To record user interactions on the webpage
B. To capture the entire webpage including all elements
C. To capture only a specific part of the webpage for focused testing
D. To speed up the browser loading time

Solution

  1. Step 1: Understand element screenshot concept

    Element screenshots capture only the selected element, not the whole page.
  2. Step 2: Compare with other screenshot types

    Full page screenshots capture everything, but element screenshots focus on one part.
  3. Final Answer:

    To capture only a specific part of the webpage for focused testing -> Option C
  4. Quick Check:

    Element screenshot = focused capture [OK]
Hint: Element screenshots capture one element, not whole page [OK]
Common Mistakes:
  • Confusing element screenshot with full page screenshot
  • Thinking it records user actions
  • Assuming it improves browser speed
2. Which Selenium Java method is used to capture a screenshot of a specific WebElement?
easy
A. takeScreenshot()
B. getScreenshotAs(OutputType.FILE)
C. captureElement()
D. saveScreenshot()

Solution

  1. Step 1: Identify the correct method for element screenshot

    The WebElement interface provides getScreenshotAs(OutputType.FILE) to capture its screenshot.
  2. Step 2: Verify other options

    Methods like takeScreenshot(), captureElement(), saveScreenshot() do not exist in Selenium Java API.
  3. Final Answer:

    getScreenshotAs(OutputType.FILE) -> Option B
  4. Quick Check:

    WebElement.getScreenshotAs = correct method [OK]
Hint: Use getScreenshotAs on WebElement for element screenshot [OK]
Common Mistakes:
  • Using driver.getScreenshotAs instead of element.getScreenshotAs
  • Choosing non-existent method names
  • Confusing with full page screenshot methods
3. What will happen if you run the following Selenium Java code snippet?
WebElement logo = driver.findElement(By.id("logo"));
File screenshot = logo.getScreenshotAs(OutputType.FILE);
System.out.println(screenshot.exists());
medium
A. Prints true if the screenshot file is saved successfully
B. Prints false because getScreenshotAs returns null
C. Throws NoSuchElementException at runtime
D. Prints the file path as a string

Solution

  1. Step 1: Understand getScreenshotAs behavior

    getScreenshotAs(OutputType.FILE) saves the element screenshot as a temporary file and returns a File object.
  2. Step 2: Check what screenshot.exists() returns

    exists() returns true if the file exists on disk, which it should after saving.
  3. Final Answer:

    Prints true if the screenshot file is saved successfully -> Option A
  4. Quick Check:

    File.exists() = true after screenshot saved [OK]
Hint: getScreenshotAs returns a File; check exists() to confirm [OK]
Common Mistakes:
  • Assuming getScreenshotAs returns null
  • Expecting file path string instead of File object
  • Ignoring possibility of NoSuchElementException if element missing
4. Identify the error in this Selenium Java code snippet for taking an element screenshot:
WebElement button = driver.findElement(By.name("submit"));
File screenshot = button.getScreenshotAs(OutputType.FILE);
FileUtils.copyFile(screenshot, new File("button.png"));
medium
A. Missing import for FileUtils causes compilation error
B. getScreenshotAs method is called on driver instead of element
C. By.name locator is invalid for buttons
D. FileUtils.copyFile requires IOException handling

Solution

  1. Step 1: Check method calls and imports

    getScreenshotAs is correctly called on the element; By.name is valid; FileUtils is commonly used from Apache Commons IO.
  2. Step 2: Identify exception handling issue

    FileUtils.copyFile throws IOException which must be handled or declared, missing here causes compile error.
  3. Final Answer:

    FileUtils.copyFile requires IOException handling -> Option D
  4. Quick Check:

    copyFile needs try/catch or throws [OK]
Hint: copyFile throws IOException; handle it with try/catch [OK]
Common Mistakes:
  • Assuming missing import causes error without checking
  • Confusing driver and element method calls
  • Thinking By.name is invalid locator
5. You want to capture screenshots of multiple elements on a page and save them with unique names. Which approach correctly implements this in Selenium Java?
List<WebElement> items = driver.findElements(By.className("product"));
int count = 1;
for (WebElement item : items) {
    File src = item.getScreenshotAs(OutputType.FILE);
    File dest = new File("product_" + count + ".png");
    FileUtils.copyFile(src, dest);
    count++;
}
hard
A. This code works but needs exception handling for copyFile
B. getScreenshotAs cannot be used in a loop for multiple elements
C. File names must be generated before the loop to avoid overwriting
D. driver.findElements returns only one element, so loop is unnecessary

Solution

  1. Step 1: Analyze the loop and screenshot logic

    The code loops over elements, takes screenshots, and saves with unique names using count variable.
  2. Step 2: Identify missing exception handling

    FileUtils.copyFile throws IOException which must be handled; otherwise code is correct.
  3. Final Answer:

    This code works but needs exception handling for copyFile -> Option A
  4. Quick Check:

    Loop + getScreenshotAs + unique names = correct, handle exceptions [OK]
Hint: Use loop with count for unique names; handle IOException [OK]
Common Mistakes:
  • Thinking getScreenshotAs can't be used multiple times
  • Not incrementing count causing file overwrite
  • Misunderstanding findElements returns multiple elements
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10 questions~5 mineasy hard