[Solved] What will the following code output?import numpy as np import scipy.optimize as opt def f(x): return (x - 3)**2 result = opt.minimize(f, 0) print(round(result.x[0], 2)) | SciPy

SciPy - Integration with Scientific Ecosystem

What will the following code output?

import numpy as np
import scipy.optimize as opt

def f(x):
    return (x - 3)**2

result = opt.minimize(f, 0)
print(round(result.x[0], 2))

AError

B0.00

C1.50

D3.00

Step-by-Step Solution

Solution:

Step 1: Understand the function and initial guess
The function f(x) = (x-3)^2 has a minimum at x=3. The initial guess is 0.
Step 2: Use SciPy's minimize to find the minimum
opt.minimize finds the minimum near the initial guess, which is 3.
Final Answer:
3.00 -> Option D
Quick Check:
Optimization result = 3.00 [OK]

Quick Trick: SciPy optimize finds function minimum near initial guess [OK]

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