[Solved] What will be the output of print(np.round(vals, 3)) in the following code?import numpy as np from scipy.sparse.linalg import eigsh M = np.... | SciPy

SciPy - Sparse Linear Algebra

What will be the output of print(np.round(vals, 3)) in the following code?

import numpy as np
from scipy.sparse.linalg import eigsh

M = np.array([[4, 1], [1, 3]])
vals, vecs = eigsh(M, k=2, which='LA')
print(np.round(vals, 3))

A[4.000 3.000]

B[5.000 2.000]

C[3.000 4.000]

D[4.618 2.382]

Step-by-Step Solution

Solution:

Step 1: Understand matrix and parameters
Matrix M is symmetric. which='LA' returns largest algebraic eigenvalues.
Step 2: Calculate eigenvalues
Eigenvalues of M are approximately 4.618 and 2.382.
Final Answer:
[4.618 2.382] -> Option D
Quick Check:
Check eigenvalues with np.linalg.eigvals [OK]

Quick Trick: which='LA' returns largest eigenvalues [OK]

Common Mistakes:

Confusing which='LA' with smallest eigenvalues
Rounding incorrectly

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What will be the output of print(np.round(vals, 3)) in the following code?

Step 1: Understand matrix and parameters

Step 2: Calculate eigenvalues

Final Answer:

Quick Check:

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