You want to solve Ax = b where A is a sparse matrix but not square (e.g., 3x2). What will happen if you use spsolve(A, b)?

hard📝 Application Q9 of 15

SciPy - Sparse Linear Algebra

You want to solve Ax = b where A is a sparse matrix but not square (e.g., 3x2). What will happen if you use spsolve(A, b)?

AIt will raise an error because <code>A</code> must be square

BIt will solve the system using least squares automatically

CIt will convert <code>A</code> to dense and solve

DIt will ignore extra rows in <code>b</code>

Step-by-Step Solution

Solution:

Step 1: Check requirements for spsolve
spsolve requires a square matrix to solve linear systems.
Step 2: Understand behavior with non-square matrices
Using a non-square matrix will cause an error because the system is not well-defined for direct solving.
Final Answer:
It will raise an error because A must be square -> Option A
Quick Check:
spsolve requires square matrices [OK]

Quick Trick: Check matrix shape; spsolve needs square matrices [OK]

Common Mistakes:

Master "Sparse Linear Algebra" in SciPy

9 interactive learning modes - each teaches the same concept differently

Want More Practice?

15+ quiz questions · All difficulty levels · Free

More SciPy Quizzes