[Solved] Given the code below, what is the shape of zoomed_img? import numpy as np from scipy.ndimage import zoom img = np.zeros((10, 10)) zoomed_img = zoom(img, zoom=1.5, order=3) | SciPy

SciPy - Image Processing (scipy.ndimage)

Given the code below, what is the shape of zoomed_img?

import numpy as np
from scipy.ndimage import zoom
img = np.zeros((10, 10))
zoomed_img = zoom(img, zoom=1.5, order=3)

A(15, 10)

B(10, 10)

C(20, 20)

D(15, 15)

Step-by-Step Solution

Solution:

Step 1: Understand zoom factor effect on shape
The zoom factor 1.5 multiplies each dimension by 1.5. Original shape is (10, 10).
Step 2: Calculate new shape
10 * 1.5 = 15 for both height and width, so new shape is (15, 15).
Final Answer:
(15, 15) -> Option D
Quick Check:
Shape scaled by 1.5 = (15, 15) [OK]

Quick Trick: Multiply each dimension by zoom factor for new shape [OK]

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Given the code below, what is the shape of zoomed_img?