Median and uniform filters in SciPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to apply a median filter to the array.

SciPy

from scipy.ndimage import median_filter
import numpy as np

arr = np.array([1, 2, 80, 4, 5])
filtered = median_filter(arr, size=[1])
print(filtered)

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A3

B5

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using size=0 or size=1 which does not change the array.

Using an even number for size which is less common for median filters.

The median_filter function requires the size parameter to specify the window size. A size of 3 means the median is computed over 3 elements.

2fill in blank

medium

Complete the code to apply a uniform filter with a window size of 4.

SciPy

from scipy.ndimage import uniform_filter
import numpy as np

arr = np.array([10, 20, 30, 40, 50])
filtered = uniform_filter(arr, size=[1])
print(filtered)

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A3

B2

C5

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Using size=3 or size=5 which changes the smoothing window.

Confusing size with the array length.

The uniform_filter smooths the array by averaging over a window of the given size. Here, size=4 means averaging over 4 elements.

3fill in blank

hard

Fix the error in the code to correctly apply a median filter with size 3.

SciPy

from scipy.ndimage import median_filter
import numpy as np

arr = np.array([5, 10, 15, 20, 25])
filtered = median_filter(arr, [1])
print(filtered)

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Asize=3

Bwindow=3

Clength=3

Dfilter_size=3

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect parameter names like window or length.

Omitting the parameter name and just passing a number.

The correct parameter name for the window size in median_filter is size. Using other names causes an error.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its length only if the length is greater than 3.

SciPy

words = ['data', 'is', 'fun', 'and', 'easy']
lengths = {word: [1] for word in words if [2]
print(lengths)

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Alen(word)

Blen(word) > 3

Cword.startswith('a')

Dword == 'data'

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using a condition unrelated to length.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if length is greater than 2.

SciPy

words = ['Hi', 'Data', 'AI', 'Science']
result = { [1]: [2] for word in words if [3] }
print(result)

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Aword.upper()

Blen(word)

Clen(word) > 2

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase instead of uppercase for keys.

Not filtering words by length correctly.

The dictionary comprehension maps the uppercase version of each word (word.upper()) to its length (len(word)) only if the length is greater than 2 (len(word) > 2).