Fitting custom models in SciPy - Time & Space Complexity
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When fitting custom models using scipy, it is important to understand how the time needed grows as the data size increases.
We want to know how the number of calculations changes when we fit models to more data points.
Analyze the time complexity of the following code snippet.
import numpy as np
from scipy.optimize import curve_fit
def model_func(x, a, b):
return a * np.exp(b * x)
xdata = np.linspace(0, 4, 50)
ydata = model_func(xdata, 2.5, 1.3) + 0.2 * np.random.normal(size=xdata.size)
popt, pcov = curve_fit(model_func, xdata, ydata)
This code fits a custom exponential model to data points using scipy's curve_fit function.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Evaluating the model function many times during optimization.
- How many times: The optimizer calls the model function repeatedly, often hundreds of times, depending on convergence.
As the number of data points increases, the model function must be evaluated on each point every time the optimizer tries new parameters.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | Few hundred evaluations x 10 points = ~thousands |
| 100 | Few hundred evaluations x 100 points = ~tens of thousands |
| 1000 | Few hundred evaluations x 1000 points = ~hundreds of thousands |
Pattern observation: The total work grows roughly linearly with the number of data points.
Time Complexity: O(n)
This means the time to fit the model grows roughly in direct proportion to the number of data points.
[X] Wrong: "The fitting time depends only on the number of parameters, not the data size."
[OK] Correct: Each fitting step evaluates the model on all data points, so more data means more work even if parameters stay the same.
Understanding how fitting time grows helps you explain performance in real projects and shows you can reason about algorithm costs beyond just writing code.
"What if the model function was very complex and took longer to compute per point? How would that affect the overall time complexity?"
Practice
scipy.optimize.curve_fit in fitting custom models?Solution
Step 1: Understand the role of curve_fit
curve_fitis used to adjust parameters of a model function so that it best fits the given data points.Step 2: Identify the correct purpose
It does not plot data, generate random data, or calculate means. Its main job is parameter estimation for fitting.Final Answer:
To find the best parameters that make the model fit the data -> Option AQuick Check:
curve_fit finds best parameters [OK]
- Thinking curve_fit plots data automatically
- Confusing curve_fit with data generation functions
- Assuming curve_fit calculates statistics like mean
curve_fit that fits a line y = m*x + c?Solution
Step 1: Check parameter order for curve_fit
The model function must have the independent variable as the first argument, followed by parameters to fit.Step 2: Verify function matches y = m*x + c
def model(x, m, c): return m * x + c correctly definesmodel(x, m, c)returningm * x + c. Others have wrong order or formula.Final Answer:
def model(x, m, c): return m * x + c -> Option BQuick Check:
Model args: x first, then parameters [OK]
- Swapping parameter and variable order
- Missing parameters in function definition
- Using wrong formula inside the function
print(popt)?
import numpy as np
from scipy.optimize import curve_fit
def model(x, a, b):
return a * np.exp(b * x)
xdata = np.array([0, 1, 2, 3])
ydata = np.array([1, 2.7, 7.4, 20.1])
popt, _ = curve_fit(model, xdata, ydata)
print(np.round(popt, 2))Solution
Step 1: Understand the model and data
The model isa * exp(b * x). Given ydata roughly follows exponential growth, parameters a and b will be close to 1.Step 2: Check output of curve_fit
Running the code fits parameters close to a=1.0 and b=0.99 (data approximates e^x but slightly less). Rounded to two decimals, popt is approximately [1.0 0.99].Final Answer:
[1.0 0.99] -> Option AQuick Check:
Exponential fit params ~ [1.0, 0.99] [OK]
- Misestimating parameters as [1.0 1.0] due to data approximation
- Confusing parameter order
- Expecting runtime errors without cause
curve_fit?
import numpy as np
from scipy.optimize import curve_fit
def quad(x, a, b, c):
return a * x**2 + b * x + c
xdata = np.array([1, 2, 3, 4])
ydata = np.array([3, 7, 13, 21])
popt, pcov = curve_fit(quad, ydata, xdata)
print(popt)Solution
Step 1: Check curve_fit arguments
curve_fit expects the model, xdata (independent), then ydata (dependent). Here, ydata and xdata are swapped.Step 2: Identify the error impact
Swapping causes wrong fitting or runtime errors because the model expects x values first.Final Answer:
The independent and dependent variables are swapped in curve_fit call -> Option CQuick Check:
curve_fit(xdata, ydata) order matters [OK]
- Swapping xdata and ydata in curve_fit
- Assuming model formula is incorrect
- Thinking initial guess is always required
y = a * sin(b * x) + c to noisy data. Which approach correctly fits the model and plots the result?Solution
Step 1: Define the correct model function
Model must be defined asmodel(x, a, b, c)returninga * np.sin(b * x) + c.Step 2: Use curve_fit and plot results
Callcurve_fit(model, xdata, ydata)to get parameters, then plot original data and fitted curve for comparison.Final Answer:
Define model with def model(x, a, b, c): return a * np.sin(b * x) + c, use curve_fit with data, then plot original and fitted curves -> Option DQuick Check:
Model function + curve_fit + plot = correct approach [OK]
- Passing np.sin directly without parameters
- Skipping model function definition
- Not storing or using fitted parameters for plotting
