Basin-hopping for global minima in SciPy - Time & Space Complexity
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We want to understand how the time needed to find the lowest point using basin-hopping changes as the problem size grows.
How does the number of steps and calculations grow when we try to find the global minimum?
Analyze the time complexity of the following code snippet.
from scipy.optimize import basinhopping
def func(x):
return x**4 - 3*x**3 + 2
result = basinhopping(func, x0=[0], niter=100)
print(result.x, result.fun)
This code tries to find the lowest value of a function by jumping around and checking many points.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Running local minimizations repeatedly after random jumps.
- How many times: The local minimization runs once per iteration, here 100 times.
Each iteration runs a local search that depends on the problem size, and the total steps grow with the number of iterations.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 100 local searches, each with small cost |
| 100 | 100 local searches, each more costly due to bigger input |
| 1000 | 100 local searches, each much more costly as input grows |
Pattern observation: The total time grows roughly with the number of iterations times the cost of each local search, which grows with input size.
Time Complexity: O(n \times m)
This means the time grows with the number of iterations m times the cost of local minimization on input size n.
[X] Wrong: "The time only depends on the number of iterations, not the input size."
[OK] Correct: Each local search inside an iteration depends on input size, so bigger problems take longer per step.
Understanding how iterative optimization methods scale helps you explain algorithm choices clearly and confidently.
"What if we increase the number of iterations instead of input size? How would the time complexity change?"
Practice
Solution
Step 1: Understand the goal of basin-hopping
Basin-hopping is designed to find the lowest point (global minimum) in complex functions that have many dips (local minima).Step 2: Compare with other options
Options A, B, and C describe unrelated tasks: differentiation, regression, and sorting, which are not the purpose of basin-hopping.Final Answer:
To find the global minimum of a function with many local minima -> Option DQuick Check:
Basin-hopping = global minimum search [OK]
- Confusing basin-hopping with simple optimization methods
- Thinking it sorts or differentiates functions
- Assuming it only finds local minima
Solution
Step 1: Recall correct import syntax in Python
To import a specific function from a module, use 'from module import function'.Step 2: Match with scipy.optimize and basinhopping
The basin-hopping function is inside scipy.optimize, so the correct import is 'from scipy.optimize import basinhopping'.Final Answer:
from scipy.optimize import basinhopping -> Option CQuick Check:
Correct import syntax = from scipy.optimize import basinhopping [OK]
- Using incorrect import order or syntax
- Trying to import basin-hopping directly from scipy
- Using 'import basinhopping from ...' which is invalid
import numpy as np
from scipy.optimize import basinhopping
def func(x):
return (x - 3)**2 + 5
result = basinhopping(func, x0=0, niter=5)
print(round(result.fun, 2))Solution
Step 1: Understand the function and its minimum
The function is (x - 3)^2 + 5, which has its minimum value at x=3, and the minimum value is 5.Step 2: Analyze basin-hopping output
Basin-hopping tries to find the global minimum. Starting at x0=0, after 5 iterations, it should find near x=3, so the function value is near 5.Final Answer:
5.00 -> Option AQuick Check:
Minimum value of (x-3)^2+5 = 5 [OK]
- Confusing minimum value with x-coordinate
- Assuming starting point is the minimum
- Ignoring the constant +5 in the function
from scipy.optimize import basinhopping
def f(x):
return x**2
result = basinhopping(f, x0=[1, 2], niter=10)
print(result.x)Solution
Step 1: Check input types for basin-hopping
basinhopping accepts x0 as a scalar or array-like. A list like [1, 2] is valid and converted to numpy array internally.Step 2: Verify function output
Function f(x) = x**2. For vector x = np.array([1,2]), it returns np.array([1,4]), not a scalar. Optimization requires scalar objective function value.Step 3: Test code behavior
The code raises an error because the objective function returns an array instead of scalar.Final Answer:
Function f must return a scalar, but it returns a list -> Option BQuick Check:
Objective func must return scalar [OK]
- Assuming no error; overlooking non-scalar function return
- Thinking x0 list causes the error
- Believing x0 must be scalar or explicit numpy array
Solution
Step 1: Understand basin-hopping parameters
'stepsize' controls how big the random jumps are between local minimizations. Bigger steps help jump out of local minima.Step 2: Evaluate options
Decreasing 'niter' reduces attempts, lowering success. Setting 'minimizer_kwargs' to None disables local minimization, which is needed. Fixed start without randomization limits exploration.Final Answer:
Increase the 'stepsize' parameter to allow bigger jumps -> Option AQuick Check:
Bigger stepsize = better escape from local minima [OK]
- Reducing iterations thinking it speeds up convergence
- Disabling local minimization by setting minimizer_kwargs to None
- Using fixed start point limits search space
