Why linear algebra is the foundation of scientific computing in SciPy - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a 2x2 matrix using NumPy.

SciPy

import numpy as np
matrix = np.array([1])

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A[[1, 2], [3, 4]]

B[1, 2, 3, 4]

C[[1, 2, 3], [4, 5, 6]]

D[1, 2]

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a flat list instead of a list of lists.

Creating a matrix with wrong dimensions.

The correct way to create a 2x2 matrix is by passing a list of lists representing rows.

2fill in blank

medium

Complete the code to compute the dot product of two vectors using NumPy.

SciPy

import numpy as np
v1 = np.array([1, 2, 3])
v2 = np.array([4, 5, 6])
dot_product = np.[1](v1, v2)

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Amultiply

Bdot

Ccross

Dsum

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiply which returns element-wise multiplication.

Using cross which computes the cross product.

The np.dot function computes the dot product of two vectors.

3fill in blank

hard

Fix the error in the code to compute the inverse of a matrix using SciPy.

SciPy

from scipy import linalg
import numpy as np
matrix = np.array([[1, 2], [3, 4]])
inverse = linalg.[1](matrix)

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Ainverse

Binvert

Cinversed

Dinv

Attempts:

3 left

💡 Hint

Common Mistakes

Using non-existent functions like inverse or invert.

Misspelling the function name.

The correct SciPy function to compute the inverse of a matrix is linalg.inv.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its length only if the length is greater than 3.

SciPy

words = ['data', 'science', 'is', 'fun']
lengths = {word: [1] for word in words if [2]

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Alen(word)

Bword

Clen(word) > 3

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself instead of its length as the value.

Comparing the word string directly to a number.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps each uppercase word to its length only if the length is greater than 2.

SciPy

words = ['AI', 'ML', 'Data', 'Code']
result = { [1]: [2] for word in words if [3] }

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Aword.upper()

Blen(word)

Clen(word) > 2

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of uppercase.

Not filtering words by length correctly.

The comprehension maps each word converted to uppercase (word.upper()) to its length (len(word)) only if the length is greater than 2 (len(word) > 2).