[Solved] What will be the output of this code snippet? import numpy as np from scipy import integrate result = integrate.quad(lambda x: np.exp(-x**2), 0, 1) print(round(result[0], 4)) | SciPy

SciPy - Basics and Scientific Computing

What will be the output of this code snippet?

import numpy as np
from scipy import integrate

result = integrate.quad(lambda x: np.exp(-x**2), 0, 1)
print(round(result[0], 4))

A1.0000

B0.7468

C0.5000

DError: integrate.quad not found

Step-by-Step Solution

Solution:

Step 1: Understand the function being integrated
The function is exp(-x^2), integrated from 0 to 1.
Step 2: Use SciPy's integrate.quad to compute the integral
integrate.quad returns a tuple; the first element is the integral value. The integral of exp(-x^2) from 0 to 1 is approximately 0.7468.
Final Answer:
0.7468 -> Option B
Quick Check:
Integral of exp(-x^2) from 0 to 1 ≈ 0.7468 [OK]

Quick Trick: Remember integrate.quad returns (value, error) tuple [OK]

Common Mistakes:

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What will be the output of this code snippet?