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Solving linear systems (solve) in SciPy - Mini Project: Build & Apply

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Solving linear systems (solve)
📖 Scenario: You work as a data analyst for a small company. You need to solve a system of linear equations to find unknown values that represent quantities of products sold.
🎯 Goal: Build a Python program that uses scipy.linalg.solve to find the solution of a system of linear equations.
📋 What You'll Learn
Create a 2D list called A representing the coefficients matrix of the system
Create a list called b representing the constants vector
Use scipy.linalg.solve to solve the system Ax = b
Print the solution vector
💡 Why This Matters
🌍 Real World
Solving linear systems is common in engineering, physics, and economics to find unknown quantities from known relationships.
💼 Career
Data scientists and analysts often solve linear systems when working with models, optimizations, and simulations.
Progress0 / 4 steps
1
Create the coefficients matrix A
Create a 2D list called A with these exact rows: [3, 1] and [1, 2].
SciPy
Hint

Think of A as a list of lists, where each inner list is a row of numbers.

2
Create the constants vector b
Create a list called b with these exact values: 9 and 8.
SciPy
Hint

b is a list with the numbers on the right side of the equations.

3
Use scipy.linalg.solve to solve the system
Import solve from scipy.linalg and create a variable called solution by calling solve(A, b).
SciPy
Hint

Use from scipy.linalg import solve to import the function.

4
Print the solution vector
Print the variable solution to display the solution of the system.
SciPy
Hint

Use print(solution) to show the answer.

Practice

(1/5)
1. What does the scipy.linalg.solve function do in solving linear systems?
easy
A. It finds the exact solution vector for a system of linear equations.
B. It approximates the solution using random guesses.
C. It only checks if the system has any solution without solving.
D. It multiplies two matrices together.

Solution

  1. Step 1: Understand the purpose of scipy.linalg.solve

    This function is designed to solve linear systems of the form Ax = b, where A is a matrix and b is a vector.
  2. Step 2: Identify the output of the function

    The function returns the vector x that exactly satisfies the equation Ax = b.
  3. Final Answer:

    It finds the exact solution vector for a system of linear equations. -> Option A
  4. Quick Check:

    Function purpose = exact solution vector [OK]
Hint: Remember: solve() returns exact solutions, not guesses. [OK]
Common Mistakes:
  • Thinking solve() approximates solutions
  • Confusing solve() with matrix multiplication
  • Assuming solve() only checks for solution existence
2. Which of the following is the correct way to import the solve function from scipy.linalg?
easy
A. from scipy.linalg import solve
B. import solve from scipy.linalg
C. from scipy import solve.linalg
D. import scipy.solve.linalg

Solution

  1. Step 1: Recall Python import syntax for functions

    To import a specific function from a module, use from module import function.
  2. Step 2: Match the correct module and function

    The function solve is inside the scipy.linalg module, so the correct import is from scipy.linalg import solve.
  3. Final Answer:

    from scipy.linalg import solve -> Option A
  4. Quick Check:

    Correct import syntax = from scipy.linalg import solve [OK]
Hint: Use 'from module import function' for specific imports. [OK]
Common Mistakes:
  • Using 'import solve from ...' which is invalid syntax
  • Trying to import submodules as functions
  • Using dot notation incorrectly in import statements
3. What is the output of this code?
import numpy as np
from scipy.linalg import solve
A = np.array([[2, 1], [1, 3]])
b = np.array([10, 15])
x = solve(A, b)
print(x)
medium
A. [4. 3.]
B. [3. 4.]
C. [2. 5.]
D. [5. 2.]

Solution

  1. Step 1: Set up the system of equations

    The matrix A and vector b represent the system:
    2x + y = 10
    x + 3y = 15
  2. Step 2: Solve the system manually

    Solving manually:
    Multiply first equation by 3: 6x + 3y = 30
    Subtract second equation: 5x = 15 -> x = 3
    y = 10 - 2*3 = 4
    Thus, x = [3. 4.], which matches the output of solve(A, b).
  3. Final Answer:

    [3. 4.] -> Option B
  4. Quick Check:

    solve(A,b) output = [3. 4.] [OK]
Hint: Trust solve() output for exact numeric solutions. [OK]
Common Mistakes:
  • Mixing up order of solution vector
  • Trying to solve manually without decimals
  • Assuming integer solutions only
4. What is wrong with this code snippet?
import numpy as np
from scipy.linalg import solve
A = np.array([[1, 2], [2, 4]])
b = np.array([5, 10])
x = solve(A, b)
print(x)
medium
A. The code will run and print the solution without issues.
B. Vector b has wrong shape and causes a syntax error.
C. The import statement is incorrect.
D. Matrix A is singular (not invertible), so solve() will raise an error.

Solution

  1. Step 1: Check matrix A properties

    Matrix A = [[1, 2], [2, 4]] has rows that are multiples (second row = 2 * first row), so it is singular (determinant = 0).
  2. Step 2: Understand solve() behavior with singular matrices

    Since A is singular, it cannot be inverted, so solve() will raise a LinAlgError indicating the matrix is singular.
  3. Final Answer:

    Matrix A is singular (not invertible), so solve() will raise an error. -> Option D
  4. Quick Check:

    Singular matrix causes error in solve() [OK]
Hint: Check if matrix rows are multiples before solving. [OK]
Common Mistakes:
  • Ignoring singular matrix errors
  • Assuming solve() works for all matrices
  • Confusing vector shape errors with matrix singularity
5. You have a system of 3 equations with 3 unknowns:
A = [[1, 2, 3], [0, 1, 4], [5, 6, 0]]
b = [11, 7, 28]

Using scipy.linalg.solve, what is the solution vector x?
hard
A. [1. 2. 3.]
B. [0. 1. 2.]
C. [2. 3. 1.]
D. [3. 1. 2.]

Solution

  1. Step 1: Write the system of equations

    The system is:
    1x + 2y + 3z = 11
    0x + 1y + 4z = 7
    5x + 6y + 0z = 28
  2. Step 2: Solve the system using substitution

    From second equation: y = 7 - 4z
    Substitute into first: x + 2(7 - 4z) + 3z = 11 -> x + 14 - 8z + 3z = 11 -> x - 5z = -3 -> x = -3 + 5z
    Substitute into third: 5(-3 + 5z) + 6(7 - 4z) = 28 -> -15 + 25z + 42 - 24z = 28 -> z + 27 = 28 -> z = 1
    y = 7 - 4*1 = 3
    x = -3 + 5*1 = 2
    Thus, x = [2. 3. 1.]
  3. Final Answer:

    [2. 3. 1.] -> Option C
  4. Quick Check:

    solve(A,b) = [2. 3. 1.] [OK]
Hint: Use solve() to avoid manual errors in 3x3 systems. [OK]
Common Mistakes:
  • Manual calculation errors with substitution
  • Mixing variable order in solution vector
  • Ignoring code output for complex systems
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