[Solved] What is the output of this code?import numpy as np from scipy.linalg import inv matrix = np.array([[1, 2], [3, 4]]) inverse = inv(matrix) print(np.round(inverse, 2)) | SciPy

SciPy - Linear Algebra (scipy.linalg)

What is the output of this code?

import numpy as np
from scipy.linalg import inv
matrix = np.array([[1, 2], [3, 4]])
inverse = inv(matrix)
print(np.round(inverse, 2))

A[[4.0 -2.0] [-3.0 1.0]]

B[[1.0 0.0] [0.0 1.0]]

C[[0.5 -0.5] [-1.5 2.0]]

D[[-2.0 1.0] [1.5 -0.5]]

Step-by-Step Solution

Solution:

Step 1: Calculate the inverse of the matrix manually
Matrix = [[1,2],[3,4]]; determinant = 1*4 - 2*3 = -2; inverse = (1/det)*[[4,-2],[-3,1]] = [[-2,1],[1.5,-0.5]]
Step 2: Compare with printed rounded output
Rounded to 2 decimals, inverse matches [[-2.0 1.0] [1.5 -0.5]].
Final Answer:
[[-2.0 1.0]\n [1.5 -0.5]] -> Option D
Quick Check:
Inverse calculation = Correct matrix inverse [OK]

Quick Trick: Inverse formula: 1/det * swap and negate elements [OK]

Common Mistakes:

MISTAKES

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What is the output of this code?