Percentiles and quantiles in SciPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to calculate the 50th percentile of the data array using scipy.

SciPy

from scipy import stats
import numpy as np
data = np.array([10, 20, 30, 40, 50])
percentile_50 = stats.scoreatpercentile(data, [1])
print(percentile_50)

Drag options to blanks, or click blank then click option'

A25

B50

C75

D100

Attempts:

3 left

💡 Hint

Common Mistakes

Using 25 or 75 instead of 50 for the median percentile.

Confusing percentile value with data values.

The 50th percentile corresponds to the median value, so we use 50 as the percentile value.

2fill in blank

medium

Complete the code to calculate the 0.25 quantile (25th percentile) of the data using scipy's percentile function.

SciPy

from scipy import stats
import numpy as np
data = np.array([5, 15, 25, 35, 45])
quantile_25 = stats.scoreatpercentile(data, [1])
print(quantile_25)

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A0.25

B0.75

C25

D75

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0.25 instead of 25 for the percentile argument.

Mixing up 25th and 75th percentiles.

The 25th percentile corresponds to the 0.25 quantile, but scipy expects percentile values between 0 and 100, so use 25.

3fill in blank

hard

Fix the error in the code to correctly calculate the 75th percentile using scipy.

SciPy

from scipy import stats
import numpy as np
data = np.array([2, 4, 6, 8, 10])
percentile_75 = stats.scoreatpercentile(data, [1])
print(percentile_75)

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A75

B0.75

C7.5

D0.25

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0.75 instead of 75.

Using a data value instead of percentile value.

Percentiles in scipy are given as values between 0 and 100, so 75 is correct for the 75th percentile.

4fill in blank

hard

Fill both blanks to create a dictionary of word lengths for words longer than 3 characters.

SciPy

words = ['apple', 'bat', 'carrot', 'dog', 'elephant']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of len(word) for the value.

Using < instead of > in the condition.

We want the length of each word (len(word)) and only include words longer than 3 characters (len(word) > 3).

5fill in blank

hard

Fill all three blanks to create a dictionary of uppercase words and their lengths for words longer than 4 characters.

SciPy

words = ['apple', 'bat', 'carrot', 'dog', 'elephant']
result = { [1]: [2] for word in words if len(word) [3] 4 }
print(result)

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Aword.upper()

Blen(word)

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using word instead of word.upper() for keys.

Using < instead of > in the condition.

The dictionary keys are uppercase words (word.upper()), values are lengths (len(word)), and we filter words longer than 4 characters (len(word) > 4).