Pearson correlation in SciPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the function for Pearson correlation from scipy.stats.

SciPy

from scipy.stats import [1]

Drag options to blanks, or click blank then click option'

Apearson

Bpearson_corr

Ccorrelation

Dpearsonr

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'pearson' instead of 'pearsonr'.

Trying to import 'correlation' which does not exist.

Using 'pearson_corr' which is not a valid function.

The function to calculate Pearson correlation in scipy.stats is pearsonr.

2fill in blank

medium

Complete the code to calculate the Pearson correlation coefficient between lists x and y.

SciPy

corr, p_value = pearsonr([1], y)

Drag options to blanks, or click blank then click option'

Adata_x

Blist_x

Cx

Dvalues_x

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a variable that does not exist like 'data_x'.

Passing the second list 'y' twice.

Using a wrong variable name.

The variable holding the first list is named x, so it should be passed to pearsonr.

3fill in blank

hard

Fix the error in the code to correctly calculate the Pearson correlation coefficient.

SciPy

corr, p_value = pearsonr(x, [1])

Drag options to blanks, or click blank then click option'

Ax

By

Cdata

Dz

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the same list twice.

Passing a variable that does not exist.

Swapping the order of arguments incorrectly.

The second argument to pearsonr should be the second data list y.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, but only for words longer than 3 characters.

SciPy

{word: [1] for word in words if [2]

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Alen(word)

Bword

Clen(word) > 3

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the word variable in the condition instead of its length.

Using incorrect comparison operators.

The dictionary comprehension uses len(word) as the value and filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys and their lengths as values, only for words longer than 4 characters.

SciPy

{ [1]: [2] for word in words if [3] }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

Clen(word) > 4

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase instead of uppercase for keys.

Using the word itself instead of its length for values.

Incorrect filter condition.

The dictionary keys are uppercase words using word.upper(), values are lengths with len(word), and the filter keeps words longer than 4 characters with len(word) > 4.