NumPy array foundation review in SciPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a NumPy array from a Python list.

SciPy

import numpy as np
arr = np.[1]([1, 2, 3, 4])

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Arange

Blist

Cmatrix

Darray

Attempts:

3 left

💡 Hint

Common Mistakes

Using np.list instead of np.array

Trying to use np.range which creates sequences, not arrays

The np.array function converts a Python list into a NumPy array.

2fill in blank

medium

Complete the code to find the shape of a NumPy array.

SciPy

import numpy as np
arr = np.array([[1, 2], [3, 4], [5, 6]])
shape = arr.[1]

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Ashape

Blen

Cdim

Dsize

Attempts:

3 left

💡 Hint

Common Mistakes

Using size which returns total elements, not shape

Trying to call len() which only returns the first dimension

The shape attribute returns the dimensions of the array as a tuple.

3fill in blank

hard

Fix the error in the code to correctly create a 2D NumPy array filled with zeros.

SciPy

import numpy as np
arr = np.zeros([1])

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A5

B(5, 5)

C[5]

D5, 5

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a single integer instead of a tuple

Passing a list instead of a tuple

Passing two separate arguments instead of a tuple

The np.zeros function requires a tuple to specify the shape of the array.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

SciPy

words = ['apple', 'bat', 'cat', 'doggy']
lengths = {word: [1] for word in words if [2]

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Alen(word)

Blen(word) > 3

Cword

Dlen(word) < 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length

Using the wrong condition like less than 3

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths if length is greater than 2.

SciPy

words = ['hi', 'hello', 'hey']
result = { [1]: [2] for word in words if [3] }

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Aword.upper()

Blen(word)

Clen(word) > 2

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of uppercase

Not filtering words by length

Mapping words instead of their lengths

The comprehension maps the uppercase version of each word to its length, filtering words longer than 2 characters.