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SciPydata~5 mins

Eigenvalues and eigenvectors (eig) in SciPy - Time & Space Complexity

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Time Complexity: Eigenvalues and eigenvectors (eig)
O(n^3)
Understanding Time Complexity

We want to understand how the time to find eigenvalues and eigenvectors changes as the matrix size grows.

How does the work increase when the matrix gets bigger?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


import numpy as np
from scipy.linalg import eig

n = 10  # Example size
A = np.random.rand(n, n)  # Create a random n x n matrix
values, vectors = eig(A)  # Compute eigenvalues and eigenvectors
    

This code creates a square matrix and computes its eigenvalues and eigenvectors using scipy.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Internal matrix factorizations and transformations to find eigenvalues and eigenvectors.
  • How many times: These operations involve multiple passes over the n x n matrix, roughly proportional to n cubed steps.
How Execution Grows With Input

As the matrix size n grows, the work needed grows much faster than n or n squared.

Input Size (n)Approx. Operations
10About 1,000 operations
100About 1,000,000 operations
1000About 1,000,000,000 operations

Pattern observation: The operations grow roughly by the cube of n, so doubling n makes the work about eight times bigger.

Final Time Complexity

Time Complexity: O(n^3)

This means the time to find eigenvalues and eigenvectors grows roughly with the cube of the matrix size.

Common Mistake

[X] Wrong: "Finding eigenvalues is as fast as simple loops over the matrix, like O(n^2)."

[OK] Correct: The process involves complex matrix operations that require more work than just looking at each element once.

Interview Connect

Knowing how eigenvalue computations scale helps you understand performance in data science tasks like PCA or stability analysis.

Self-Check

"What if the matrix is sparse instead of dense? How would the time complexity change?"