[Solved] What is the output of this code snippet? from scipy.stats import binom n, p = 4, 0.3 prob = binom.pmf(2, n, p) print(round(prob, 3)) | SciPy

SciPy - Statistical Functions (scipy.stats) Basics

What is the output of this code snippet?

from scipy.stats import binom
n, p = 4, 0.3
prob = binom.pmf(2, n, p)
print(round(prob, 3))

A0.345

B0.411

C0.264

D0.123

Step-by-Step Solution

Solution:

Step 1: Calculate binomial PMF for k=2, n=4, p=0.3
Using formula or scipy, probability = C(4,2) * 0.3^2 * 0.7^2 = 6 * 0.09 * 0.49 = 0.2646 approx.
Step 2: Round the result to 3 decimals
Rounded to 3 decimals, 0.2646 becomes 0.264.
Final Answer:
0.264 -> Option C
Quick Check:
binom.pmf(2,4,0.3) ≈ 0.264 [OK]

Quick Trick: Use scipy or formula to get exact PMF value [OK]

Common Mistakes:

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What is the output of this code snippet?