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You want to calculate the photon energy for a wavelength of 550 nm and print the result in electronvolts (eV). Which code snippet correctly performs this using scipy.constants?

hard📝 Application Q8 of 15
SciPy - Constants and Special Functions
You want to calculate the photon energy for a wavelength of 550 nm and print the result in electronvolts (eV). Which code snippet correctly performs this using scipy.constants?
Afrom scipy.constants import c, planck, electron_volt wavelength = 550e-9 energy_joule = planck * c / wavelength energy_ev = energy_joule / electron_volt print(round(energy_ev, 3))
Bfrom scipy.constants import c, planck wavelength = 550 energy = planck * c / wavelength print(energy)
Cfrom scipy.constants import planck, electron_volt wavelength = 550e-9 energy_ev = planck / wavelength / electron_volt print(energy_ev)
Dfrom scipy.constants import c, planck, electron_volt wavelength = 550e-9 energy_ev = planck * c * wavelength * electron_volt print(energy_ev)
Step-by-Step Solution
Solution:
  1. Step 1: Convert wavelength to meters

    550 nm = 550e-9 meters, needed for correct calculation.
  2. Step 2: Calculate energy in joules

    Energy = planck * c / wavelength.
  3. Step 3: Convert joules to electronvolts

    Divide energy in joules by electron_volt constant.
  4. Step 4: Verify code snippets

    from scipy.constants import c, planck, electron_volt wavelength = 550e-9 energy_joule = planck * c / wavelength energy_ev = energy_joule / electron_volt print(round(energy_ev, 3)) correctly imports all constants, converts units, calculates energy, and prints rounded eV value.
  5. Final Answer:

    Option A -> Option A
  6. Quick Check:

    Convert joules to eV by dividing by electron_volt [OK]
Quick Trick: Energy (eV) = (planck * c / wavelength) / electron_volt [OK]
Common Mistakes:
MISTAKES
  • Not converting wavelength to meters
  • Multiplying instead of dividing by electron_volt
  • Omitting electron_volt conversion

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