Saturate and desaturate in SASS - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the saturate() function do in Sass?

It increases the color's saturation, making the color look more vivid or intense.

beginner

What effect does the desaturate() function have on a color in Sass?

It decreases the color's saturation, making the color look more gray or dull.

beginner

How do you use saturate() in Sass? Provide a simple example.

Example:
color: saturate(#6699cc, 20%);
This makes the blue color 20% more saturated.

intermediate

What happens if you saturate a fully saturated color in Sass?

The color stays the same because it cannot get more saturated than 100%.

intermediate

Why is controlling saturation useful in web design?

It helps create mood and focus by making colors more vivid or muted, improving user experience and visual hierarchy.

What does desaturate(#ff0000, 50%) do to the color?

A Makes it 50% less saturated (more gray)

B Makes it 50% lighter

C Makes it 50% more red

D Makes it 50% darker

desaturate() reduces the saturation, so the red becomes less vivid and more gray.

Which Sass function increases color intensity?

A lighten()

B desaturate()

C darken()

D saturate()

saturate() increases the saturation, making colors more vivid.

If a color is fully desaturated, what color is it?

A Black

B Gray

C Original color

D White

A fully desaturated color loses all color and becomes gray.

What unit is used to specify saturation change in saturate() and desaturate()?

A Percent (%)

B Pixels

C Degrees

D Em units

Saturation changes are given as percentages.

Which Sass function would you use to make a color less vivid?

A lighten()

B saturate()

C desaturate()

D adjust-hue()

desaturate() reduces saturation, making colors less vivid.

Explain how saturate() and desaturate() affect colors in Sass and why you might use them.

Think about how colors look more bright or dull.

Describe a real-life example where you would use desaturate() in a website design.

Consider how dull colors can help focus on important content.

Practice

1. What does the saturate() function do to a color in Sass?

easy

A. Makes the color darker

B. Makes the color more vivid and bright

C. Makes the color lighter

D. Makes the color more transparent

Solution

1. Step 1: Understand the purpose of saturate()

   The saturate() function increases the intensity of the color's saturation, making it look more vivid.

2. Step 2: Compare with other effects

   Unlike darkening or lightening, saturate specifically boosts color brightness and vividness.

3. Final Answer:

   Makes the color more vivid and bright -> Option B

4. Quick Check:

   saturate() = more vivid color [OK]

Hint: Saturate = boost color brightness and vividness [OK]

Common Mistakes:

• Confusing saturate() with lighten() or darken()
• Thinking saturate() changes transparency
• Assuming saturate() makes color dull

2. Which of the following is the correct syntax to desaturate a color by 20% in Sass?

easy

A. desaturate(#ff0000, 0.2)

B. desaturate(#ff0000 20%)

C. desaturate(#ff0000, 20%)

D. desaturate(#ff0000; 20%)

Solution

1. Step 1: Recall the function syntax

   The desaturate() function takes two arguments separated by a comma: the color and the percentage to reduce saturation.

2. Step 2: Identify correct punctuation and units

   The percentage must have a percent sign (%) and be separated by a comma, so desaturate(#ff0000, 20%) is correct.

3. Final Answer:

   desaturate(#ff0000, 20%) -> Option C

4. Quick Check:

   Correct syntax uses comma and percent sign [OK]

Hint: Use comma and % for saturation amount [OK]

Common Mistakes:

• Omitting the comma between arguments
• Using decimal instead of percentage
• Using semicolon instead of comma

3. What color will this Sass code produce?

$color: #6699cc;
$new-color: saturate($color, 30%);

medium

A. A more vivid blue than #6699cc

B. #6699cc (unchanged)

C. A duller, grayer blue than #6699cc

D. A lighter blue than #6699cc

Solution

1. Step 1: Understand saturate effect on #6699cc

   The color #6699cc is a medium blue. Applying saturate($color, 30%) increases its saturation, making it more vivid.

2. Step 2: Compare options

   A more vivid blue than #6699cc correctly describes the result. The unchanged option is incorrect because the color changes. The duller, grayer option is incorrect because saturate increases vividness. The lighter blue option is incorrect because saturate does not lighten the color.

3. Final Answer:

   A more vivid blue than #6699cc -> Option A

4. Quick Check:

   saturate() = more vivid color [OK]

Hint: Saturate makes colors brighter, not lighter or duller [OK]

Common Mistakes:

• Thinking saturate lightens the color
• Assuming saturate makes color duller
• Believing color stays unchanged

4. Identify the error in this Sass code:

$color: #00ff00;
$new-color: desaturate $color 50%;

medium

A. Function name should be saturate, not desaturate

B. Incorrect color format

C. Percentage value should be a decimal

D. Missing parentheses around function arguments

Solution

1. Step 1: Check function call syntax

   In Sass, functions require parentheses around their arguments. The code misses parentheses around $color and 50%.

2. Step 2: Verify other parts

   The color format #00ff00 is valid, and the percentage is correctly given as 50%. The function name desaturate is correct for reducing saturation.

3. Final Answer:

   Missing parentheses around function arguments -> Option D

4. Quick Check:

   Functions need parentheses [OK]

Hint: Always use parentheses for Sass functions [OK]

Common Mistakes:

• Omitting parentheses in function calls
• Confusing saturate and desaturate functions
• Using decimal instead of percentage

5. You want to create a button style that uses a base color #ff6600 but looks less intense on hover by reducing saturation by 40%. Which Sass code correctly achieves this?

hard

A. $base-color: #ff6600;
button {
background-color: $base-color;
&:hover {
background-color: desaturate($base-color, 40%);
}
}

B. $base-color: #ff6600;
button {
background-color: $base-color;
&:hover {
background-color: saturate($base-color, 40%);
}
}

C. $base-color: #ff6600;
button {
background-color: $base-color;
&:hover {
background-color: desaturate($base-color 40%);
}
}

D. $base-color: #ff6600;
button {
background-color: $base-color;
&:hover {
background-color: lighten($base-color, 40%);
}
}

Solution

1. Step 1: Identify the goal

   The button's hover state should have the base color with 40% less saturation, so desaturate($base-color, 40%) is needed.

2. Step 2: Check syntax and logic

   $base-color: #ff6600; button { background-color: $base-color; &:hover { background-color: desaturate($base-color, 40%); } } uses correct syntax with parentheses and comma, and applies desaturate correctly on hover. $base-color: #ff6600; button { background-color: $base-color; &:hover { background-color: saturate($base-color, 40%); } } incorrectly saturates instead of desaturates. $base-color: #ff6600; button { background-color: $base-color; &:hover { background-color: desaturate($base-color 40%); } } misses the comma between arguments. $base-color: #ff6600; button { background-color: $base-color; &:hover { background-color: lighten($base-color, 40%); } } uses lighten, which changes brightness, not saturation.

3. Final Answer:

   Code with desaturate($base-color, 40%) and correct syntax -> Option A

4. Quick Check:

   Desaturate with parentheses and comma [OK]

Hint: Use desaturate(color, %) with parentheses and comma [OK]

Common Mistakes:

• Using saturate instead of desaturate
• Omitting comma between arguments
• Using lighten instead of desaturate