First SASS stylesheet - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a variable for the main color.

SASS

$main-color: [1];

Drag options to blanks, or click blank then click option'

A#3498db

Bcolor

Cmain-color

Dblue

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name instead of a color value.

Forgetting the semicolon at the end.

The variable $main-color is assigned the color value #3498db. In SASS, variables start with $ and store values like colors.

2fill in blank

medium

Complete the code to use the variable $main-color for the background color.

SASS

body {
  background-color: [1];
}

Drag options to blanks, or click blank then click option'

A$main-color

Bmain-color

C#fff

Dbackground

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting the $ sign before the variable.

Using a color value directly instead of the variable.

To use a SASS variable, include the $ sign before the variable name. Here, $main-color sets the background color.

3fill in blank

hard

Fix the error in the nested style by completing the selector for the h1 inside header.

SASS

header {
  background: $main-color;
  [1] {
    color: white;
  }
}

Drag options to blanks, or click blank then click option'

A.h1

Bh1

C#h1

Dheader h1

Attempts:

3 left

💡 Hint

Common Mistakes

Using class or id selectors instead of element selectors.

Repeating the parent selector inside the nested block.

In SASS, nested selectors are written simply by the element name. Here, h1 inside header is nested as h1.

4fill in blank

hard

Fill both blanks to create a nested style for nav inside header with a hover effect on links.

SASS

header {
  [1]: $main-color;
  nav {
    a {
      color: white;
      &:[2] {
        color: #f39c12;
      }
    }
  }
}

Drag options to blanks, or click blank then click option'

Abackground

Bhover

Cactive

Dborder

Attempts:

3 left

💡 Hint

Common Mistakes

Using border instead of background for color.

Using active instead of hover for mouse hover effect.

The background property sets the color for header. The &:hover selector applies styles when the mouse is over the link.

5fill in blank

hard

Fill all three blanks to create a SASS map of colors and use it to set the border color.

SASS

$colors: (
  primary: [1],
  secondary: [2]
);

.box {
  border: 2px solid map-get($colors, [3]);
}

Drag options to blanks, or click blank then click option'

A#2980b9

B#2ecc71

Cprimary

Dsecondary

Attempts:

3 left

💡 Hint

Common Mistakes

Using color values as keys instead of keys as strings.

Forgetting to use map-get to access map values.

The map $colors stores color values with keys primary and secondary. The map-get function retrieves the color by key. Here, the border uses the primary color.

Practice

1. What is the main benefit of using variables in a SASS stylesheet?

easy

A. They automatically fix CSS errors.

B. They make the stylesheet load faster in the browser.

C. They let you reuse values like colors and sizes easily.

D. They convert SASS to JavaScript.

Solution

1. Step 1: Understand what variables do in SASS

   Variables store values such as colors or sizes so you can reuse them without repeating the same value.

2. Step 2: Compare options with this understanding

   Only They let you reuse values like colors and sizes easily. correctly describes this benefit. Other options describe unrelated or incorrect features.

3. Final Answer:

   They let you reuse values like colors and sizes easily. -> Option C

4. Quick Check:

   Variables store reusable values = A [OK]

Hint: Variables store reusable values like colors or sizes [OK]

Common Mistakes:

• Thinking variables speed up browser loading
• Believing variables fix CSS errors automatically
• Confusing SASS variables with JavaScript

2. Which of the following is the correct way to declare a variable in SASS?

easy

A. $main-color: #3498db;

B. var main-color = #3498db;

C. main-color: #3498db;

D. @main-color: #3498db;

Solution

1. Step 1: Recall SASS variable syntax

   In SASS, variables start with a dollar sign ($) followed by the name, then a colon and the value.

2. Step 2: Match options to this syntax

   $main-color: #3498db; matches this exactly. Options B, C, and D use incorrect syntax.

3. Final Answer:

   $main-color: #3498db; -> Option A

4. Quick Check:

   Variables start with $ in SASS = A [OK]

Hint: Variables always start with $ in SASS [OK]

Common Mistakes:

• Using var keyword like JavaScript
• Omitting the $ sign before variable name
• Using @ instead of $ for variables

3. What will be the output CSS of this SASS code?

$primary-color: #ff0000;

.button {
  color: $primary-color;
  &:hover {
    color: darken($primary-color, 20%);
  }
}

medium

A. .button { color: $primary-color; }
.button:hover { color: darken($primary-color, 20%); }

B. Syntax error: darken function not recognized

C. .button { color: #ff0000; }
.button:hover { color: #ff3333; }

D. .button { color: #ff0000; }
.button:hover { color: #cc0000; }

Solution

1. Step 1: Understand variable substitution and nesting

   The variable $primary-color is replaced with #ff0000. The nested &:hover becomes .button:hover.

2. Step 2: Calculate darken color

   darken(#ff0000, 20%) makes the red darker, resulting in #cc0000.

3. Final Answer:

   .button { color: #ff0000; } .button:hover { color: #cc0000; } -> Option D

4. Quick Check:

   Variables replaced and nesting expanded = B [OK]

Hint: Variables replaced, nesting expands selectors [OK]

Common Mistakes:

• Leaving variables as-is in output CSS
• Not expanding nested selectors
• Misunderstanding darken color function

4. Identify the error in this SASS code:

$font-size: 16px

body {
  font-size: $font-size;
}

medium

A. body selector cannot be used in SASS

B. Missing semicolon after variable declaration

C. font-size property is invalid

D. Variable name should not start with $

Solution

1. Step 1: Check variable declaration syntax

   In SASS, each statement must end with a semicolon. The variable declaration lacks a semicolon.

2. Step 2: Verify other parts

   Variable names start with $, font-size is valid, and body selector is allowed.

3. Final Answer:

   Missing semicolon after variable declaration -> Option B

4. Quick Check:

   Semicolon missing after $font-size declaration = D [OK]

Hint: Always end variable declarations with semicolon [OK]

Common Mistakes:

• Omitting semicolon after variable
• Thinking $ is invalid for variables
• Assuming selectors can't be used

5. You want to create a SASS stylesheet where all buttons have a background color stored in a variable, and on hover, the background becomes 15% lighter. Which SASS code correctly achieves this?

hard

A. $btn-bg: #007bff;

button {
background-color: $btn-bg;
&:hover {
background-color: lighten($btn-bg, 15%);
}
}

B. $btn-bg: #007bff

button {
background-color: $btn-bg;
&:hover {
background-color: lighten($btn-bg, 15%)
}
}

C. $btn-bg: #007bff;

button {
background-color: $btn-bg;
&:hover {
background-color: darken($btn-bg, 15%);
}
}

D. $btn-bg: #007bff;

button {
background-color: $btn-bg;
&:hover {
background-color: $btn-bg + 15%;
}
}

Solution

1. Step 1: Check variable declaration and syntax

   $btn-bg: #007bff; button { background-color: $btn-bg; &:hover { background-color: lighten($btn-bg, 15%); } } correctly declares $btn-bg with a semicolon and uses proper nesting with &:hover.

2. Step 2: Verify color function usage

   $btn-bg: #007bff; button { background-color: $btn-bg; &:hover { background-color: lighten($btn-bg, 15%); } } uses lighten($btn-bg, 15%) to make the color lighter on hover, which matches the requirement.

3. Step 3: Identify errors in other options

   $btn-bg: #007bff button { background-color: $btn-bg; &:hover { background-color: lighten($btn-bg, 15%) } } misses semicolons; $btn-bg: #007bff; button { background-color: $btn-bg; &:hover { background-color: darken($btn-bg, 15%); } } darkens instead of lightens; $btn-bg: #007bff; button { background-color: $btn-bg; &:hover { background-color: $btn-bg + 15%; } } tries invalid addition of color and percentage.

4. Final Answer:

   $btn-bg: #007bff; button { background-color: $btn-bg; &:hover { background-color: lighten($btn-bg, 15%); } } -> Option A

5. Quick Check:

   Correct variable, nesting, and lighten function = C [OK]

Hint: Use lighten() with correct syntax and semicolons [OK]

Common Mistakes:

• Forgetting semicolons after declarations
• Using darken instead of lighten
• Trying to add percentage directly to color