Destructuring patterns in Rust - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to destructure the tuple and print the first value.

Rust

let tuple = (10, 20);
let ([1], _) = tuple;
println!("{}", first);

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Ax

Bfirst

Ca

Dval

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name different from the one in println! causes a compile error.

Trying to destructure without parentheses.

The variable first is used to destructure the first element of the tuple.

2fill in blank

medium

Complete the code to destructure the struct and print the name field.

Rust

struct Person { name: String, age: u8 }
let person = Person { name: String::from("Alice"), age: 30 };
let Person { [1], age: _ } = person;
println!("{}", name);

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Aname

Bage

Cperson

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using the struct name instead of the field name in the pattern.

Forgetting to ignore the unused field with underscore.

The field name is destructured from the Person struct to access the name.

3fill in blank

hard

Fix the error in the code by completing the pattern to destructure the enum variant.

Rust

enum Message {
    Quit,
    Move { x: i32, y: i32 },
}
let msg = Message::Move { x: 5, y: 10 };
match msg {
    Message::Move [1] => println!("x: {}, y: {}", x, y),
    _ => (),
}

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Ax, y

B(x, y)

C{ x, y }

D[x, y]

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses or brackets instead of curly braces for named fields.

Not matching the field names exactly.

The Move variant has named fields, so the pattern must use curly braces with field names.

4fill in blank

hard

Fill both blanks to destructure the nested tuple and print the inner values.

Rust

let nested = ((1, 2), (3, 4));
let ([1], [2]) = nested;
println!("{} {}", a, b);

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A(a, b)

Bx

Cy

D(c, d)

Attempts:

3 left

💡 Hint

Common Mistakes

Using variable names without parentheses for tuple patterns.

Not matching the nested structure correctly.

The outer tuple is destructured into two inner tuples. The first inner tuple is bound to (a, b), and the second to x (unused here).

5fill in blank

hard

Fill all three blanks to destructure a tuple and filter values greater than 5 in a comprehension.

Rust

let numbers = vec![(1, 6), (3, 4), (7, 8)];
let filtered: Vec<_> = numbers.iter()
    .filter(|&&([1], [2])| [3] > 5)
    .collect();

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Ax

By

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong variable in the filter condition.

Not destructuring the tuple correctly.

The tuple is destructured into x and y. The filter checks if y is greater than 5.