📖 Scenario: Imagine you have a sentence and you want to look at just a part of it without copying the whole sentence. This is useful when you want to save memory and work faster.
🎯 Goal: You will learn how to create and use string slices in Rust to access parts of a string.
📋 What You'll Learn
Create a string variable
Create a string slice variable
Use string slicing syntax
Print the string slice
💡 Why This Matters
🌍 Real World
String slices help programs use memory efficiently by not copying whole strings when only parts are needed.
💼 Career
Understanding string slices is important for Rust developers working on performance-critical applications like web servers or embedded systems.
Progress0 / 4 steps
1
Create a string variable
Create a variable called sentence and set it to the string "Hello, Rustaceans!".
Rust
Hint
Use let to create a variable and put the string in double quotes.
2
Create a string slice
Create a string slice called greeting that takes the first 5 characters from sentence using slicing syntax &sentence[0..5].
Rust
Hint
Use &sentence[0..5] to get a slice from index 0 up to but not including 5.
3
Use the string slice
Add a println! statement to print the greeting string slice.
Rust
Hint
Use println!("{}", greeting); to print the slice.
4
Print the result
Run the program to print the string slice greeting. The output should be Hello.
Rust
Hint
Check the output in the console. It should show Hello.
Practice
(1/5)
1. What is a string slice in Rust?
easy
A. A type of integer used for indexing strings
B. A reference to a part of a string without copying it
C. A function that modifies a string in place
D. A new string created by copying characters
Solution
Step 1: Understand string slice concept
A string slice is a reference to a part of a string, not a new string.
Step 2: Compare options
Only A reference to a part of a string without copying it describes a reference without copying, which matches string slices.
Final Answer:
A reference to a part of a string without copying it -> Option B
Quick Check:
String slice = reference without copy [OK]
Hint: Remember: slices borrow, not copy strings [OK]
Common Mistakes:
Thinking slices create new strings
Confusing slices with string modification
Believing slices are integer types
2. Which of the following is the correct syntax to get a slice of the first 4 characters from a string text?
easy
A. &text[0..4]
B. text.slice(0, 4)
C. &text[1..5]
D. text[0:4]
Solution
Step 1: Recall Rust slice syntax
Rust uses &string[start..end] to get a slice from start to end-1.
Step 2: Check options
&text[0..4] uses &text[0..4], which correctly slices first 4 chars (indices 0 to 3).
Final Answer:
&text[0..4] -> Option A
Quick Check:
Slice syntax = &string[start..end] [OK]
Hint: Use &string[start..end] for slices, not methods or colons [OK]
Common Mistakes:
Using method calls like slice() which don't exist
Using 1-based indexing instead of 0-based
Using Python-style slicing with colons
3. What will the following Rust code print?
let s = String::from("hello world");
let slice = &s[6..11];
println!("{}", slice);
medium
A. hello
B. Syntax error
C. hello world
D. world
Solution
Step 1: Understand slicing indices
The slice &s[6..11] takes characters from index 6 up to 10 (11 excluded).
Step 2: Identify substring
In "hello world", index 6 is 'w' and index 10 is 'd', so slice is "world".
Final Answer:
world -> Option D
Quick Check:
Slice &s[6..11] = "world" [OK]
Hint: Remember slice end index is excluded [OK]
Common Mistakes:
Including the end index character
Confusing start and end indices
Expecting full string output
4. Identify the error in this Rust code snippet:
let s = String::from("rustacean");
let slice = &s[0..5];
println!("{}", slice);
let invalid_slice = &s[5..15];
medium
A. The slice &s[5..15] causes a runtime panic due to out-of-bounds
B. The slice &s[0..5] is invalid syntax
C. The println! macro is missing a semicolon
D. String::from cannot create strings with length 9
Solution
Step 1: Check slice ranges
The string "rustacean" has length 9, so valid indices are 0 to 8.
Step 2: Analyze invalid slice
The slice &s[5..15] tries to access indices beyond length, causing runtime panic.
Final Answer:
The slice &s[5..15] causes a runtime panic due to out-of-bounds -> Option A
Quick Check:
Out-of-bounds slice = panic [OK]
Hint: Slice end must be ≤ string length to avoid panic [OK]
Common Mistakes:
Assuming slices auto-adjust to string length
Thinking &s[0..5] is invalid syntax
Ignoring runtime panics from invalid slices
5. Given a string text, how can you safely get a slice of the first n characters without risking a runtime panic if n is larger than the string length?
hard
A. Use text.get(0..n).unwrap()
B. Use &text[0..n] without checks
C. Use &text[0..n.min(text.len())]
D. Use &text[0..=n]
Solution
Step 1: Understand safe slicing
To avoid panic, slice end must not exceed string length.
Step 2: Use min to limit slice end
Using n.min(text.len()) ensures slice end is at most string length.
Final Answer:
Use &text[0..n.min(text.len())] -> Option C
Quick Check:
Safe slice end = min(n, length) [OK]
Hint: Use min() to limit slice end safely [OK]
Common Mistakes:
Slicing without length check causing panic
Using unwrap() which can panic if None
Using inclusive range which is invalid for slices
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