📖 Scenario: Imagine you have a box with some toys. Sometimes, you want to look at the toys without changing them. Other times, you want to rearrange or add new toys inside the box. In Rust, mutable references let you change the contents of the box safely.
🎯 Goal: You will create a simple Rust program that uses mutable references to change the value inside a variable. This will help you understand how to borrow and modify data safely.
📋 What You'll Learn
Create a variable with an initial integer value
Create a mutable reference to that variable
Use the mutable reference to change the variable's value
Print the updated value to see the change
💡 Why This Matters
🌍 Real World
Mutable references are used in Rust to safely change data without copying it. This is useful in programs that need to update information efficiently, like games or data processing tools.
💼 Career
Understanding mutable references is essential for Rust developers, especially in systems programming, embedded development, and performance-critical applications where safe memory management is crucial.
Progress0 / 4 steps
1
Create a variable with an initial value
Create a variable called number and set it to 10.
Rust
Hint
Remember to make the variable mutable by using mut so you can change it later.
2
Create a mutable reference to the variable
Create a mutable reference called number_ref to the variable number using &mut number.
Rust
Hint
Use &mut to borrow a mutable reference to the variable.
3
Change the variable's value using the mutable reference
Use the mutable reference number_ref to change the value of number to 20 by assigning *number_ref = 20.
Rust
Hint
Use the dereference operator * to change the value through the reference.
4
Print the updated value
Print the value of number using println!("{}", number) to see the updated value.
Rust
Hint
Use println!("{}", number) to display the value.
Practice
(1/5)
1. What does a mutable reference &mut allow you to do in Rust?
easy
A. Prevent any changes to the value it points to
B. Create multiple immutable references at the same time
C. Move ownership of the value to another variable
D. Change the value it points to without taking ownership
Solution
Step 1: Understand what &mut means
The &mut symbol creates a mutable reference, which means you can change the value it points to without taking ownership.
Step 2: Compare with other options
Options B and D describe immutable references or no changes allowed, and C talks about ownership transfer, which is different from mutable references.
Final Answer:
Change the value it points to without taking ownership -> Option D
Quick Check:
Mutable reference = change value without ownership [OK]
Hint: Mutable references let you change data without moving ownership [OK]
Common Mistakes:
Confusing mutable references with ownership transfer
Thinking multiple mutable references are allowed simultaneously
Believing mutable references prevent changes
2. Which of the following is the correct syntax to create a mutable reference to a variable num in Rust?
easy
A. let ref = #
B. let ref = &mut num;
C. let ref = *num;
D. let ref = mut #
Solution
Step 1: Identify the syntax for mutable references
In Rust, to create a mutable reference, you use &mut before the variable name.
Step 2: Check each option
A creates an immutable reference, B dereferences the value, and D has incorrect syntax order.
Final Answer:
let ref = &mut num; -> Option B
Quick Check:
Mutable reference syntax = &mut variable [OK]
Hint: Use &mut before variable name for mutable reference [OK]
Common Mistakes:
Forgetting the 'mut' keyword after &
Placing 'mut' before & incorrectly
Using * instead of &mut for references
3. What will be the output of the following Rust code?
fn main() {
let mut x = 5;
let r = &mut x;
*r += 1;
println!("{}", x);
}
medium
A. 6
B. Runtime panic
C. Compilation error
D. 5
Solution
Step 1: Understand the mutable reference usage
The variable x is mutable. A mutable reference r is created to x. The value pointed by r is incremented by 1 using *r += 1;.
Step 2: Determine the final value of x
Since r points to x, incrementing *r changes x from 5 to 6. The print statement outputs 6.
Final Answer:
6 -> Option A
Quick Check:
Mutable reference modifies original value = 6 [OK]
Hint: Dereference mutable ref with * to change original value [OK]
Common Mistakes:
Expecting original value unchanged
Confusing reference with copy
Thinking code causes compile error
4. What is wrong with this Rust code?
fn main() {
let mut val = 10;
let r1 = &mut val;
let r2 = &mut val;
*r1 += 1;
*r2 += 1;
println!("{}", val);
}
medium
A. Dereferencing mutable references is not allowed
B. Cannot mutate a variable declared as mutable
C. Cannot have two mutable references to the same variable at the same time
D. Missing semicolon after println!
Solution
Step 1: Identify the mutable references
The code creates two mutable references r1 and r2 to the same variable val at the same time.
Step 2: Recall Rust's borrowing rules
Rust allows only one mutable reference at a time to prevent data races. Having two mutable references simultaneously causes a compile-time error.
Final Answer:
Cannot have two mutable references to the same variable at the same time -> Option C
Quick Check:
Only one mutable reference allowed at once [OK]
Hint: Only one mutable reference allowed at a time [OK]
Common Mistakes:
Trying to create multiple mutable references simultaneously
Thinking mutable references can be copied freely
Ignoring Rust's borrowing rules
5. Given the following code, what is the correct way to safely modify the value inside data using mutable references without causing a compile error?
fn main() {
let mut data = 100;
let r1 = &data;
let r2 = &mut data;
*r2 += 50;
println!("{}", data);
}
hard
A. Remove the immutable reference r1 before creating r2
B. Change r2 to an immutable reference &data
C. Use two mutable references r1 and r2 simultaneously
D. Make data immutable by removing mut
Solution
Step 1: Understand Rust's borrowing rules
Rust does not allow mutable and immutable references to the same variable at the same time. Here, r1 is immutable and r2 is mutable, causing a conflict.
Step 2: Fix the code by removing the immutable reference
Removing r1 allows only the mutable reference r2 to exist, so modifying data through r2 is safe and allowed.
Final Answer:
Remove the immutable reference r1 before creating r2 -> Option A
Quick Check:
Mutable and immutable refs cannot coexist [OK]
Hint: Remove immutable refs before mutable refs to avoid errors [OK]
Common Mistakes:
Trying to use mutable and immutable references simultaneously
Changing mutable ref to immutable without reason
Making variable immutable but still trying to mutate
Recommended
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