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Iterating over collections in Rust - Mini Project: Build & Apply

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Iterating over collections
📖 Scenario: You are managing a small fruit store. You have a list of fruits and their prices. You want to go through each fruit and see its price.
🎯 Goal: Learn how to iterate over a collection in Rust using a for loop to access each item.
📋 What You'll Learn
Create a vector of fruit names
Create a variable to count the number of fruits
Use a for loop to iterate over the vector
Print each fruit name during iteration
💡 Why This Matters
🌍 Real World
Iterating over collections is common when you want to process lists of data, like items in a store, user inputs, or sensor readings.
💼 Career
Knowing how to loop over collections is a basic skill for software developers, data analysts, and anyone working with programming languages.
Progress0 / 4 steps
1
Create a vector of fruits
Create a vector called fruits with these exact string values: "Apple", "Banana", "Cherry", "Date".
Rust
Hint

Use vec![...] to create a vector with the given fruit names.

2
Create a counter variable
Add a variable called count and set it to 0 to count the number of fruits.
Rust
Hint

Use let mut count = 0; to create a variable that can change.

3
Iterate over the fruits vector
Use a for loop with the variable fruit to iterate over fruits.iter(). Inside the loop, increase count by 1.
Rust
Hint

Use for fruit in fruits.iter() to loop over each fruit.

4
Print each fruit and the total count
Inside the for loop, add a println! statement to print the fruit name. After the loop, print the total number of fruits using println! with the variable count.
Rust
Hint

Use println!("Fruit: {}", fruit); inside the loop and println!("Total fruits: {}", count); after the loop.

Practice

(1/5)
1. What does the following Rust code do?
let numbers = [1, 2, 3];
for num in numbers {
    println!("{}", num);
}
easy
A. Causes a compile error because arrays can't be iterated
B. Prints each number in the array on a new line
C. Prints the whole array as one line
D. Prints the length of the array

Solution

  1. Step 1: Understand the for loop over an array

    The for loop visits each element in the array named 'numbers'.
  2. Step 2: Action inside the loop

    Each element is printed on its own line using println! macro.
  3. Final Answer:

    Prints each number in the array on a new line -> Option B
  4. Quick Check:

    for loop over array prints elements one by one [OK]
Hint: For loops visit each item in order [OK]
Common Mistakes:
  • Thinking arrays can't be iterated
  • Expecting the whole array printed at once
  • Confusing print! with println!
2. Which of these is the correct syntax to iterate over a vector named v in Rust?
easy
A. for i in v { println!("{}", i); }
B. for i to v { println!("{}", i); }
C. foreach i in v { println!("{}", i); }
D. loop i in v { println!("{}", i); }

Solution

  1. Step 1: Recall Rust for loop syntax

    Rust uses 'for variable in collection' to iterate over items.
  2. Step 2: Check each option

    for i in v { println!("{}", i); } matches correct syntax; others use invalid keywords.
  3. Final Answer:

    for i in v { println!("{}", i); } -> Option A
  4. Quick Check:

    Rust uses 'for ... in ...' loops [OK]
Hint: Remember: for variable in collection [OK]
Common Mistakes:
  • Using 'to' instead of 'in'
  • Using 'foreach' which is not Rust syntax
  • Using 'loop' incorrectly
3. What is the output of this Rust code?
let v = vec![10, 20, 30];
let mut sum = 0;
for &num in &v {
    sum += num;
}
println!("{}", sum);
medium
A. 60
B. 303020
C. Error due to borrowing
D. 0

Solution

  1. Step 1: Understand iteration with references

    The loop uses '&num in &v' to borrow each element by reference and dereference it with '&num'.
  2. Step 2: Calculate sum of elements

    sum starts at 0, then adds 10, 20, and 30, resulting in 60.
  3. Final Answer:

    60 -> Option A
  4. Quick Check:

    Sum of 10+20+30 = 60 [OK]
Hint: Sum elements by iterating with references [OK]
Common Mistakes:
  • Confusing references and values
  • Expecting concatenation instead of sum
  • Thinking borrowing causes error here
4. Identify the error in this Rust code snippet:
let arr = [1, 2, 3];
for num in arr {
    num += 1;
    println!("{}", num);
}
medium
A. Loop variable 'num' must be a reference
B. Syntax error: missing semicolon after println!
C. Array cannot be iterated directly
D. Cannot modify 'num' because it is an immutable copy

Solution

  1. Step 1: Check mutability of loop variable

    In Rust, loop variables are immutable by default; 'num' is a copy of array element.
  2. Step 2: Understand why 'num += 1' fails

    Trying to change 'num' causes error because it is not declared mutable.
  3. Final Answer:

    Cannot modify 'num' because it is an immutable copy -> Option D
  4. Quick Check:

    Loop variables are immutable unless declared mutable [OK]
Hint: Loop vars are immutable unless 'mut' used [OK]
Common Mistakes:
  • Thinking semicolon missing causes error
  • Believing arrays can't be iterated
  • Assuming loop vars are references by default
5. You have a vector of strings: let words = vec!["apple", "banana", "cherry"];. How do you create a new vector containing the lengths of each word using iteration?
hard
A. let lengths = words.map(|w| w.len());
B. let lengths = for w in words { w.len() };
C. let lengths: Vec<usize> = words.iter().map(|w| w.len()).collect();
D. let lengths = words.iter().for_each(|w| w.len());

Solution

  1. Step 1: Use iterator and map to transform elements

    words.iter() creates an iterator over references to strings; map applies a function to each element.
  2. Step 2: Collect results into a new vector

    collect() gathers the mapped lengths into a Vec<usize>.
  3. Final Answer:

    let lengths: Vec<usize> = words.iter().map(|w| w.len()).collect(); -> Option C
  4. Quick Check:

    Use iter().map(...).collect() to transform collections [OK]
Hint: Use iter().map(...).collect() to build new collections [OK]
Common Mistakes:
  • Trying to use for loop as expression
  • Using map directly on vector without iter()
  • Using for_each which returns () not a collection
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10 questions~5 mineasy hard