Why functional patterns complement OOP in Ruby - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a method that returns the square of a number.

Ruby

def square(num)
  num [1] num
end

Drag options to blanks, or click blank then click option'

A+

B*

C-

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '*' will add the number to itself, not square it.

The method multiplies the number by itself to get the square.

2fill in blank

medium

Complete the code to create an array of squares from 1 to 5 using map.

Ruby

squares = (1..5).[1] { |n| n * n }

Drag options to blanks, or click blank then click option'

Amap

Beach

Cselect

Dreduce

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'each' returns the original array, not the transformed one.

The map method transforms each element by applying the block, returning a new array.

3fill in blank

hard

Fix the error in the code to filter even numbers from an array.

Ruby

evens = [1, 2, 3, 4, 5].[1] { |n| n.even? }

Drag options to blanks, or click blank then click option'

Amap

Beach

Creduce

Dselect

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'map' returns transformed elements but does not filter.

The select method filters elements based on the block's condition.

4fill in blank

hard

Fill both blanks to create a hash of word lengths for words longer than 3 characters.

Ruby

lengths = words.select { |word| word.length > 3 }.map { |word| [ [1], [2] ] }.to_h

Drag options to blanks, or click blank then click option'

Aword

Bword.length

Cword.size

Dword.upcase

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.size is valid but not the expected answer here.

The hash keys are words, and the values are their lengths using word.length.

5fill in blank

hard

Fill all three blanks to create a hash of uppercase words and their lengths for words longer than 4 characters.

Ruby

result = words.select { |word| word.length [3] 4 }.map { |word| [ [1], [2] ] }.to_h

Drag options to blanks, or click blank then click option'

Aword.upcase

Bword.length

C>

Dword.downcase

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will filter the wrong words.

The keys are uppercase words, values are their lengths, filtered by length greater than 4.

Practice

1. Which of the following best explains why functional patterns complement Object-Oriented Programming (OOP) in Ruby?

easy

A. Functional patterns make Ruby code run faster by avoiding objects.

B. Functional patterns replace the need for classes and objects entirely.

C. OOP discourages the use of methods and focuses only on data.

D. Functional patterns create small, reusable methods without side effects, improving code clarity.

Solution

1. Step 1: Understand functional patterns in Ruby

   Functional patterns emphasize small, reusable methods that avoid changing data outside their scope (no side effects).

2. Step 2: Understand OOP's role

   OOP organizes code around objects that combine data and behavior, making programs easier to manage.

3. Final Answer:

   Functional patterns create small, reusable methods without side effects, improving code clarity. -> Option D

4. Quick Check:

   Functional patterns improve clarity by avoiding side effects [OK]

Hint: Functional = small, pure methods; OOP = objects with data [OK]

Common Mistakes:

• Thinking functional replaces OOP completely
• Believing OOP ignores methods
• Assuming functional always makes code faster

2. Which Ruby syntax correctly defines a pure function that doubles a number without changing any external state?

easy

A. def double(x); x * 2; end

B. def double(x); @value = x * 2; end

C. def double(x); puts x * 2; end

D. def double(x); x *= 2; nil; end

Solution

1. Step 1: Identify pure function characteristics

   A pure function returns a value based only on input and does not change external variables or produce side effects.

2. Step 2: Check each option

   def double(x); x * 2; end returns x * 2 without changing anything else. def double(x); @value = x * 2; end changes an instance variable (@value), so it has side effects. def double(x); puts x * 2; end prints output (side effect). def double(x); x *= 2; nil; end modifies x locally but returns nil, so it doesn't return the doubled value.

3. Final Answer:

   def double(x); x * 2; end -> Option A

4. Quick Check:

   Pure function returns value only [OK]

Hint: Pure functions return values without side effects [OK]

Common Mistakes:

• Using instance variables inside pure functions
• Printing inside functions instead of returning
• Not returning the computed value explicitly

3. What is the output of this Ruby code combining OOP and functional style?

class Calculator
  def initialize(value)
    @value = value
  end

  def double
    @value * 2
  end

  def apply(func)
    func.call(@value)
  end
end

calc = Calculator.new(5)
puts calc.double
puts calc.apply(->(x) { x + 3 })

medium

A. 10
8

B. 10
15

C. 5
8

D. Error: undefined method

Solution

1. Step 1: Understand the Calculator class methods

   The double method returns @value * 2, so for 5 it returns 10. The apply method calls the passed function with @value.

2. Step 2: Evaluate the output of puts statements

   calc.double prints 10. calc.apply calls the lambda adding 3 to 5, so prints 8.

3. Final Answer:

   10 8 -> Option A

4. Quick Check:

   double = 10, apply adds 3 = 8 [OK]

Hint: Remember lambdas called with .call and return values [OK]

Common Mistakes:

• Confusing lambda call syntax
• Expecting apply to modify @value
• Mixing up output values

4. Identify the error in this Ruby code that tries to combine functional and OOP styles:

class Counter
  def initialize
    @count = 0
  end

  def increment
    @count += 1
  end

  def apply(func)
    func(@count)
  end
end

counter = Counter.new
counter.increment
puts counter.apply(->(x) { x * 2 })

medium

A. Lambda syntax is incorrect

B. increment method should return @count

C. func should be called with .call, not func()

D. Instance variable @count is not initialized

Solution

1. Step 1: Check how func is used in apply method

   In Ruby, to call a lambda or Proc, you must use .call, not func().

2. Step 2: Identify the error

   func(@count) will cause a NoMethodError because func is a Proc object and needs .call.

3. Final Answer:

   func should be called with .call, not func() -> Option C

4. Quick Check:

   Call lambdas with .call [OK]

Hint: Use .call to invoke lambdas or Procs [OK]

Common Mistakes:

• Calling lambda like a normal method
• Forgetting to initialize instance variables
• Incorrect lambda syntax

5. You want to create a Ruby class that stores a list of numbers and provides a method to return a new list with each number doubled, without changing the original list. Which approach best combines functional patterns with OOP?

hard

A. Modify the original list inside the method by doubling each element in place.

B. Define a method that returns a new array using map without modifying the original list.

C. Store the doubled values in an instance variable and return it directly.

D. Use a global variable to hold the doubled list and update it inside the method.

Solution

1. Step 1: Understand the requirement

   The method should not change the original list but return a new list with doubled values.

2. Step 2: Evaluate options for functional and OOP style

   Using map returns a new array without side effects, fitting functional style. Modifying original data or using global variables breaks this principle.

3. Final Answer:

   Define a method that returns a new array using map without modifying the original list. -> Option B

4. Quick Check:

   Use map for new array, avoid side effects [OK]

Hint: Use map to transform arrays without changing originals [OK]

Common Mistakes:

• Modifying original array instead of returning new
• Using global variables for data storage
• Storing results in instance variables unnecessarily