[Solved] What will this Ruby code output? class Greeter def greet(name) "Hello, #{name}!" end end greet_lambda = ->(name) { "Hi, #{name}!" } g = Greeter.new puts g.greet("Alice") puts greet_lambda.call("Bob") | Ruby

Ruby - Functional Patterns in Ruby

What will this Ruby code output?

class Greeter
  def greet(name)
    "Hello, #{name}!"
  end
end

greet_lambda = ->(name) { "Hi, #{name}!" }

g = Greeter.new
puts g.greet("Alice")
puts greet_lambda.call("Bob")

AHello, Alice! Hello, Bob!

BHi, Alice! Hello, Bob!

CHello, Alice! Hi, Bob!

DHi, Alice! Hi, Bob!

Step-by-Step Solution

Solution:

Step 1: Identify outputs of greet method and lambda
g.greet("Alice") returns "Hello, Alice!"; greet_lambda.call("Bob") returns "Hi, Bob!".
Step 2: Confirm output order
First puts prints greet result, second puts prints lambda result.
Final Answer:
Hello, Alice! Hi, Bob! -> Option C
Quick Check:
Method and lambda outputs combined = Hello, Alice! and Hi, Bob! [OK]

Quick Trick: Method and lambda produce different greetings [OK]

Common Mistakes:

Mixing up which greeting belongs to method or lambda
Forgetting to call lambda with .call
Assuming both greetings are the same

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What will this Ruby code output?

Step 1: Identify outputs of greet method and lambda

Step 2: Confirm output order

Final Answer:

Quick Check:

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