[Solved] What is the output of this Ruby code combining OOP and functional style?class Calculator def initialize(value) @value = value end def double @value * 2 end def apply(func) func.... | Ruby

Ruby - Functional Patterns in Ruby

What is the output of this Ruby code combining OOP and functional style?

class Calculator
  def initialize(value)
    @value = value
  end

  def double
    @value * 2
  end

  def apply(func)
    func.call(@value)
  end
end

calc = Calculator.new(5)
puts calc.double
puts calc.apply(->(x) { x + 3 })

A10 8

B10 15

C5 8

DError: undefined method

Step-by-Step Solution

Solution:

Step 1: Understand the Calculator class methods
The double method returns @value * 2, so for 5 it returns 10. The apply method calls the passed function with @value.
Step 2: Evaluate the output of puts statements
calc.double prints 10. calc.apply calls the lambda adding 3 to 5, so prints 8.
Final Answer:
10 8 -> Option A
Quick Check:
double = 10, apply adds 3 = 8 [OK]

Quick Trick: Remember lambdas called with .call and return values [OK]

Common Mistakes:

Confusing lambda call syntax
Expecting apply to modify @value
Mixing up output values

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What is the output of this Ruby code combining OOP and functional style?

Step 1: Understand the Calculator class methods

Step 2: Evaluate the output of puts statements

Final Answer:

Quick Check:

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