[Solved] Identify the error in this Ractor code snippet: r = Ractor.new do Ractor.yield 10 20 end puts r.take puts r.take | Ruby

Ruby - Concurrent Programming

Identify the error in this Ractor code snippet:

r = Ractor.new do
  Ractor.yield 10
  20
end
puts r.take
puts r.take

ARactor.new requires arguments

BSecond r.take call will cause Ractor::Closed error

CNo error, code runs fine

DCalling Ractor.yield inside Ractor block is invalid

Step-by-Step Solution

Solution:

Step 1: Understand Ractor.yield and r.take
Ractor.yield sends a value to the main thread, and r.take receives it. The first r.take gets 10.
Step 2: Analyze second r.take call
The block returns 20 after yield, which is the final value. The second r.take gets 20. After that, the Ractor is closed. A third r.take would cause error, but here only two calls are made, so no error.
Step 3: Check the code carefully
Both r.take calls are valid; no error occurs.
Final Answer:
No error, code runs fine -> Option C
Quick Check:
Ractor.yield and take work twice safely [OK]

Quick Trick: Ractor.yield sends values, take receives them sequentially [OK]

Common Mistakes:

Master "Concurrent Programming" in Ruby

9 interactive learning modes - each teaches the same concept differently

More Ruby Quizzes

Identify the error in this Ractor code snippet: