Ruby - Concurrent Programming
What will be the output of this Ruby code using Ractor?
r = Ractor.new { 5 * 5 }
result = r.take
puts resultWhat will be the output of this Ruby code using Ractor?
medium📝 Predict Output Q13 of 15
Step-by-Step Solution
Solution:
Step 1: Understand Ractor block execution
The block{ 5 * 5 }runs inside the Ractor and returns 25.Step 2: Use
taketo get the resultr.takereceives the value returned by the Ractor block, which is 25.Final Answer:
25 -> Option DQuick Check:
Ractor returns 25, take receives it [OK]
Quick Trick: Ractor block returns value, take fetches it [OK]
Common Mistakes:
- Expecting string '5 * 5' instead of calculation
- Confusing take with yield
- Assuming nil or error without communication
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