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Rubyprogramming~10 mins

Immutable data with freeze in Ruby - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to freeze the string so it cannot be changed.

Ruby
name = "Ruby".[1]
name << "Lang"
Drag options to blanks, or click blank then click option'
Aupcase
Bfreeze
Creverse
Dcapitalize
Attempts:
3 left
💡 Hint
Common Mistakes
Using string methods that modify content instead of freezing.
Not calling any method and expecting immutability.
2fill in blank
medium

Complete the code to freeze the array so it cannot be modified.

Ruby
numbers = [1, 2, 3].[1]
numbers << 4
Drag options to blanks, or click blank then click option'
Areverse
Bsort
Cfreeze
Duniq
Attempts:
3 left
💡 Hint
Common Mistakes
Using sorting or reversing methods instead of freezing.
Trying to modify without freezing first.
3fill in blank
hard

Fix the error by freezing the hash so it cannot be changed.

Ruby
config = {mode: 'dark', volume: 10}
config.[1]
config[:mode] = 'light'
Drag options to blanks, or click blank then click option'
Afreeze
Bdelete
Cdup
Dclear
Attempts:
3 left
💡 Hint
Common Mistakes
Using methods that remove or copy instead of freezing.
Not freezing before trying to modify.
4fill in blank
hard

Fill both blanks to create a frozen array and check if it is frozen.

Ruby
arr = [10, 20, 30].[1]
puts arr.[2]
Drag options to blanks, or click blank then click option'
Afreeze
Bfrozen?
Cempty?
Dlength
Attempts:
3 left
💡 Hint
Common Mistakes
Using empty? or length instead of frozen?.
Not freezing the array before checking.
5fill in blank
hard

Fill all three blanks to freeze a nested hash and check if the nested array is frozen.

Ruby
settings = {theme: 'blue', options: [1, 2, 3]}
settings = settings.[1]
puts settings[:options].[2]
settings[:options].[3]
Drag options to blanks, or click blank then click option'
Afreeze
Bfrozen?
Ddup
Attempts:
3 left
💡 Hint
Common Mistakes
Assuming freezing outer hash freezes nested objects.
Not freezing nested array separately.

Practice

(1/5)
1. What does the freeze method do to an object in Ruby?
easy
A. Prevents any further modifications to the object
B. Deletes the object from memory
C. Duplicates the object
D. Makes the object mutable

Solution

  1. Step 1: Understand the purpose of freeze

    The freeze method is used to make an object immutable, meaning it cannot be changed after freezing.
  2. Step 2: Identify the effect on the object

    Once frozen, any attempt to modify the object will raise an error, so it prevents further changes.
  3. Final Answer:

    Prevents any further modifications to the object -> Option A
  4. Quick Check:

    freeze makes object immutable = Prevents changes [OK]
Hint: Freeze means no changes allowed after calling it [OK]
Common Mistakes:
  • Thinking freeze deletes the object
  • Confusing freeze with duplication
  • Assuming freeze makes object mutable
2. Which of the following is the correct way to freeze a string name in Ruby?
easy
A. freeze(name)
B. name.frozen = true
C. name.freeze()
D. freeze name

Solution

  1. Step 1: Recall Ruby method call syntax

    In Ruby, to call a method on an object, use dot notation like object.method().
  2. Step 2: Identify the correct freeze syntax

    The correct way to freeze the string name is name.freeze(). Other options are invalid syntax or incorrect usage.
  3. Final Answer:

    name.freeze() -> Option C
  4. Quick Check:

    Method call with dot and parentheses = Correct freeze syntax [OK]
Hint: Use dot notation: object.freeze() to freeze [OK]
Common Mistakes:
  • Using freeze as a standalone function
  • Trying to assign frozen = true
  • Omitting dot before freeze
3. What will be the output of this Ruby code?
arr = [1, 2, 3]
arr.freeze
arr << 4
puts arr.inspect
medium
A. [1, 2, 3, 4]
B. RuntimeError: can't modify frozen Array
C. [1, 2, 3]
D. SyntaxError

Solution

  1. Step 1: Understand freezing the array

    The array arr is frozen using arr.freeze, making it immutable.
  2. Step 2: Analyze the modification attempt

    Trying to append 4 with arr << 4 will raise a RuntimeError because the array is frozen and cannot be changed.
  3. Final Answer:

    RuntimeError: can't modify frozen Array -> Option B
  4. Quick Check:

    Frozen object + modification = RuntimeError [OK]
Hint: Modifying frozen object causes RuntimeError [OK]
Common Mistakes:
  • Assuming frozen array can still be changed
  • Expecting silent failure or no error
  • Confusing output with syntax error
4. Identify the error in this Ruby code snippet:
str = "hello"
str.freeze
str[0] = 'H'
puts str
medium
A. RuntimeError: can't modify frozen String
B. SyntaxError due to invalid string modification
C. No error, output is "Hello"
D. Output is "hello" without changes

Solution

  1. Step 1: Recognize string freezing effect

    The string str is frozen, so it cannot be changed after str.freeze.
  2. Step 2: Understand the attempted modification

    Trying to change the first character with str[0] = 'H' raises a RuntimeError because the string is frozen.
  3. Final Answer:

    RuntimeError: can't modify frozen String -> Option A
  4. Quick Check:

    Frozen string + modification = RuntimeError [OK]
Hint: Frozen string cannot be changed, causes RuntimeError [OK]
Common Mistakes:
  • Thinking string changes silently fail
  • Expecting output "Hello" without error
  • Confusing syntax error with runtime error
5. Given this code, what is the best way to safely modify a frozen array without error?
original = [10, 20, 30].freeze
# Your code here to add 40
hard
A. original.freeze(false)
B. original << 40
C. original.push(40)
D. original = original.dup << 40

Solution

  1. Step 1: Understand frozen array cannot be changed

    The array original is frozen, so direct modification like << or push will cause errors.
  2. Step 2: Use duplication to create a modifiable copy

    Using original.dup creates a new unfrozen copy. Then appending 40 to this copy is allowed.
  3. Step 3: Assign the modified copy back

    Assigning the new array with 40 added back to original variable safely updates it without error.
  4. Final Answer:

    original = original.dup << 40 -> Option D
  5. Quick Check:

    Duplicate frozen object before modifying = Safe change [OK]
Hint: Duplicate frozen object before changing it [OK]
Common Mistakes:
  • Trying to modify frozen array directly
  • Using non-existent freeze(false) method
  • Assuming push works on frozen array
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