[Solved] Given this code, what will be the output?def repeat(n) n.times { yield } end count = 0 repeat(3) do count += 1 puts count end | Ruby

Ruby - Blocks, Procs, and Lambdas

Given this code, what will be the output?

def repeat(n)
  n.times { yield }
end
count = 0
repeat(3) do
  count += 1
  puts count
end

A1 2 3 (each on a new line)

B3 3 3 (each on a new line)

C0 1 2 (each on a new line)

DNo output

Step-by-Step Solution

Solution:

Step 1: Understand the repeat method with yield
The method calls the block n times using n.times { yield }.
Step 2: Trace the block execution
Each time the block runs, it increments count by 1 and prints it. So it prints 1, then 2, then 3 on separate lines.
Final Answer:
1 2 3 (each on a new line) -> Option A
Quick Check:
yield with times increments count = A [OK]

Quick Trick: yield calls the block passed to the method [OK]

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