[Solved] Find the error in this Ruby code snippet:score = 85 case score when 90..100 puts "A" when 80..89 puts "B" when 70..79 puts "C" else puts "F" endWhy does it not print "B" for score 85? | Ruby

Ruby - Control Flow

Find the error in this Ruby code snippet:

score = 85
case score
when 90..100
  puts "A"
when 80..89
  puts "B"
when 70..79
  puts "C"
else
  puts "F"
end

Why does it not print "B" for score 85?

ARanges in when must be strings, not numbers.

B

The case statement compares score with ranges incorrectly; use <code>case</code> with <code>when</code> and <code>===</code>.

CThe code is correct; it will print "B" as expected.

DThe ranges overlap and cause confusion.

Step-by-Step Solution

Solution:

Step 1: Understand how case/when works with ranges
Ruby's case/when uses the === operator, which works with ranges to check if a value is inside.
Step 2: Check the given score and ranges
Score 85 falls inside 80..89, so puts "B" will run correctly.
Final Answer:
The code is correct; it will print "B" as expected. -> Option C
Quick Check:
Ranges work with case/when using === [OK]

Quick Trick: Ranges work naturally in when clauses with case [OK]

Common Mistakes:

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