What is the output of this Ruby code?

medium📝 Predict Output Q13 of 15

Ruby - String Operations

str = "cat"
str[1] = 'o'
puts str

Acat

Bc t

Ccot

DError

Step-by-Step Solution

Solution:

Step 1: Understand string indexing and assignment
str[1] = 'o' changes the character at index 1 (second character) from 'a' to 'o'.
Step 2: Apply the change and print
Original string "cat" becomes "cot" after the change, so puts prints "cot".
Final Answer:
cot -> Option C
Quick Check:
Changing index 1 to 'o' = cot [OK]

Quick Trick: Index 1 means second character in string [OK]

Common Mistakes:

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