Ruby - Arrays
Given two arrays a = [1, 2, 3, 4] and b = [3, 4, 5, 6], how can you find elements that are in either array but not in both?
Given two arrays a = [1, 2, 3, 4] and b = [3, 4, 5, 6], how can you find elements that are in either array but not in both?
hard📝 Application Q9 of 15
Step-by-Step Solution
Solution:
Step 1: Understand symmetric difference
Elements in either array but not both is called symmetric difference.Step 2: Use union minus intersection
Calculate union(a | b)and subtract intersection(a & b)to get symmetric difference.Final Answer:
Use(a | b) - (a & b)for symmetric difference -> Option DQuick Check:
Symmetric difference = union - intersection [OK]
Quick Trick: Symmetric difference = (a | b) - (a & b) [OK]
Common Mistakes:
- Using only & or |
- Using + instead of |
- Confusing difference with symmetric difference
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