LTRIM for list capping in Redis - Time & Space Complexity
We want to understand how the time it takes to trim a Redis list changes as the list gets bigger.
Specifically, how does the LTRIM command behave when keeping a list capped at a certain size?
Analyze the time complexity of the following Redis commands used to cap a list size.
LPUSH mylist "new_item"
LTRIM mylist 0 99
This code adds a new item to the start of the list and then trims the list to keep only the first 100 items.
Look for operations that repeat or scale with input size.
- Primary operation: The LTRIM command removes elements outside the specified range.
- How many times: It processes elements outside the kept range, which depends on how many items exceed the cap.
The time to trim depends on how many extra items are removed beyond the cap.
| Input Size (n) | Approx. Operations |
|---|---|
| 100 | Few or no removals if list is at cap |
| 1,000 | Removes about 900 items if trimming to 100 |
| 10,000 | Removes about 9,900 items if trimming to 100 |
Pattern observation: The more items beyond the cap, the more work LTRIM does, growing roughly linearly with the number of removed items.
Time Complexity: O(m)
This means the time grows linearly with the number of elements removed from the list during trimming.
[X] Wrong: "LTRIM always runs in constant time regardless of list size."
[OK] Correct: LTRIM must remove all elements outside the range, so if many elements are removed, it takes more time.
Understanding how commands like LTRIM scale helps you reason about performance in real systems and shows you can think about resource use clearly.
"What if we changed the trim range to keep more items, say 0 to 999 instead of 0 to 99? How would the time complexity change?"
Practice
LTRIM mylist 0 9 do to the list mylist?Solution
Step 1: Understand LTRIM parameters
The commandLTRIM mylist 0 9keeps elements from index 0 to 9 inclusive.Step 2: Effect on list size
This means only the first 10 elements remain; all others are removed.Final Answer:
Keeps only the first 10 elements of the list and removes the rest. -> Option DQuick Check:
LTRIM 0 9 keeps first 10 elements [OK]
- Confusing start and stop indexes
- Thinking it removes first 10 instead of keeping them
- Assuming it keeps last 10 elements
tasks using LTRIM?Solution
Step 1: Understand negative indexes in LTRIM
Negative indexes count from the end: -1 is last element, -5 is fifth from last.Step 2: Select correct range for last 5 elements
UsingLTRIM tasks -5 -1keeps elements from fifth last to last, i.e., last 5 elements.Final Answer:
LTRIM tasks -5 -1 -> Option AQuick Check:
Negative indexes keep last elements [OK]
- Using positive indexes to try to keep last elements
- Reversing negative indexes order
- Using invalid syntax with start > stop
colors with elements ["red", "green", "blue", "yellow", "purple"], what will be the list content after executing LTRIM colors 1 3?Solution
Step 1: Identify indexes to keep
LTRIM colors 1 3 keeps elements from index 1 to 3 inclusive.Step 2: Extract elements at those indexes
Indexes 1 to 3 are "green", "blue", "yellow".Final Answer:
["green", "blue", "yellow"] -> Option AQuick Check:
LTRIM keeps specified index range [OK]
- Including element at index 0 by mistake
- Confusing index ranges
- Assuming LTRIM removes elements inside range
LTRIM mylist 5 2 on a Redis list. What will happen?Solution
Step 1: Understand LTRIM behavior with start > stop
If start index is greater than stop index, Redis trims the list to empty.Step 2: Apply to given command
Since 5 > 2,LTRIM mylist 5 2empties the list.Final Answer:
The list will be emptied because start index is greater than stop index. -> Option BQuick Check:
LTRIM with start > stop empties list [OK]
- Expecting an error instead of empty list
- Thinking list remains unchanged
- Assuming it keeps elements in reverse order
chatlog. Which sequence of commands correctly caps the list size after adding a new message "Hello"?Solution
Step 1: Understand list direction and adding new messages
UsingLPUSHadds new messages to the start (index 0), so recent messages are at the front.Step 2: Use LTRIM to keep first 20 elements
To keep the most recent 20 messages, trim to indexes 0 to 19, or equivalentlyLTRIM chatlog 0 19. Negative indexes also work but must match direction.Step 3: Match push and trim commands
SinceLPUSHadds to front,LTRIM chatlog 0 19keeps first 20 recent messages. LPUSH chatlog "Hello"; LTRIM chatlog -20 -1 usesLPUSHandLTRIM chatlog -20 -1, which keeps last 20 elements, but since new messages are at front, last 20 are oldest. So LPUSH chatlog "Hello"; LTRIM chatlog -20 -1 is incorrect.Step 4: Correct option
LPUSH chatlog "Hello"; LTRIM chatlog 0 19 usesLPUSHandLTRIM chatlog 0 19, which correctly keeps the 20 most recent messages at front.Final Answer:
LPUSH chatlog "Hello"; LTRIM chatlog 0 19 -> Option CQuick Check:
LPUSH + LTRIM 0 19 keeps recent 20 messages [OK]
- Using RPUSH but trimming front indexes
- Using negative indexes incorrectly with LPUSH
- Trimming wrong range causing oldest messages to stay
Ready to prove it?
Pass the test and this pattern moves unknown
