Lifting state up in React Native - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to lift the state up by passing the state value as a prop.

React Native

function Parent() {
  const [count, setCount] = React.useState(0);
  return <Child count=[1] />;
}

Drag options to blanks, or click blank then click option'

A0

BsetCount

Ccount

Dprops.count

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the setter function instead of the state value.

Passing a constant instead of the state variable.

The parent component passes the current state value count as a prop to the child.

2fill in blank

medium

Complete the code to lift the state up by passing the setter function as a prop.

React Native

function Parent() {
  const [count, setCount] = React.useState(0);
  return <Child onIncrement=[1] />;
}

Drag options to blanks, or click blank then click option'

AsetCount

Bcount

C() => setCount(count + 1)

Dincrement

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the state value instead of the setter function.

Passing a function call instead of the function itself.

The parent passes the setter function setCount so the child can update the state.

3fill in blank

hard

Fix the error in the child component to call the passed setter function correctly.

React Native

function Child({ onIncrement }) {
  return <Button title="Add" onPress=[1] />;
}

Drag options to blanks, or click blank then click option'

AonIncrement()

B() => onIncrement()

ConIncrement

D() => onIncrement

Attempts:

3 left

💡 Hint

Common Mistakes

Calling the function immediately instead of passing a function.

Passing the function reference without wrapping when parameters are needed.

The onPress expects a function. Wrapping onIncrement() in an arrow function ensures it is called only when pressed.

4fill in blank

hard

Fill both blanks to lift state up and handle input change in the parent.

React Native

function Parent() {
  const [text, setText] = React.useState('');
  return <Child value=[1] onChangeText=[2] />;
}

Drag options to blanks, or click blank then click option'

Atext

BsetText

C() => setText

Dtext => setText(text)

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the setter function directly without wrapping.

Passing a function that does not accept the new text parameter.

The parent passes the current text state and a function to update it when the child input changes.

5fill in blank

hard

Fill all three blanks to lift state up and display the updated count in the parent.

React Native

function Parent() {
  const [count, setCount] = React.useState(0);
  return (
    <>
      <Child count=[1] onIncrement=[2] />
      <Text>Count: [3]</Text>
    </>
  );
}

Drag options to blanks, or click blank then click option'

Acount

BsetCount

Ccount + 1

Dcount.toString()

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the wrong value to the Text component.

Passing a calculation instead of the state variable.

The parent passes the current count, the setter function, and displays the count as text.

Practice

1. What is the main purpose of lifting state up in React Native?

easy

A. To create multiple independent states in child components

B. To move shared state to a common parent component so children can access it

C. To store state only inside child components without sharing

D. To avoid using props for data sharing between components

Solution

1. Step 1: Understand the concept of shared state

   Lifting state up means moving state to a common parent so multiple children can use it.

2. Step 2: Identify the purpose of lifting state up

   This helps keep data consistent and allows children to communicate through the parent.

3. Final Answer:

   To move shared state to a common parent component so children can access it -> Option B

4. Quick Check:

   Lifting state up = shared parent state [OK]

Hint: Shared data lives in parent to sync children easily [OK]

Common Mistakes:

• Thinking each child should have its own separate state
• Believing lifting state up removes the need for props
• Confusing lifting state up with component styling

2. Which of the following is the correct way to pass a state update function from a parent to a child component in React Native?

easy

A.

B.

C.

D.

Solution

1. Step 1: Identify what to pass as prop

   The parent passes a function to update state, not the state value or setState method directly.

2. Step 2: Choose the correct syntax

   Passing updateStateFunction as a prop is correct to allow child to call it.

3. Final Answer:

   <Child updateState={updateStateFunction} /> -> Option C

4. Quick Check:

   Pass update function as prop = <Child updateState={updateStateFunction} /> [OK]

Hint: Pass functions, not state or setState directly [OK]

Common Mistakes:

• Passing the entire state object instead of a function
• Passing setState method directly without binding
• Passing state value instead of update function

3. Given the code below, what will be the output when the button in Child is pressed?

function Parent() {
  const [count, setCount] = React.useState(0);
  return (
    <>
      <Child count={count} increment={() => setCount(count + 1)} />
      <Text>Count: {count}</Text>
    </>
  );
}

function Child({ count, increment }) {
  return <Button title={`Add`} onPress={increment} />;
}

medium

A. The app will crash due to incorrect state update

B. The count will always stay 0 regardless of button presses

C. The button will not respond to presses

D. The count displayed will increase by 1 each time the button is pressed

Solution

1. Step 1: Understand state and props flow

   The Parent holds the count state and passes it plus an increment function to Child.

2. Step 2: Analyze what happens on button press

   Pressing the button calls increment, which updates count by adding 1.

3. Final Answer:

   The count displayed will increase by 1 each time the button is pressed -> Option D

4. Quick Check:

   State update via lifted function increments count [OK]

Hint: Button calls parent's update function to increase count [OK]

Common Mistakes:

• Thinking count won't update because it's passed as prop
• Assuming setCount is not called correctly
• Confusing local and lifted state

4. Identify the error in this lifting state up example:

function Parent() {
  const [text, setText] = React.useState('');
  return <Child text={text} setText={setText()} />;
}

function Child({ text, setText }) {
  return <TextInput value={text} onChangeText={setText} />;
}

medium

A. setText is called immediately instead of passing the function

B. text state is not initialized properly

C. Child component should not receive setText as prop

D. TextInput should not use onChangeText prop

Solution

1. Step 1: Check how setText is passed as prop

   In Parent, setText={setText()} calls setText immediately instead of passing the function.

2. Step 2: Correct way to pass setText

   It should be setText={setText} to pass the function reference.

3. Final Answer:

   setText is called immediately instead of passing the function -> Option A

4. Quick Check:

   Pass function reference, not call it [OK]

Hint: Pass function, don't call it when passing as prop [OK]

Common Mistakes:

• Calling setState function instead of passing it
• Confusing state value with update function
• Ignoring React hooks rules

5. You have two sibling components, TemperatureInputCelsius and TemperatureInputFahrenheit, that need to share temperature data. How should you use lifting state up to keep both inputs in sync?

hard

A. Move the temperature state to their common parent and pass value and update functions as props

B. Keep separate states in each sibling and update independently

C. Store temperature state only in one sibling and let the other read it directly

D. Use global variables outside React components to share temperature

Solution

1. Step 1: Identify the need for shared state

   Both siblings need to reflect the same temperature, so state must be shared.

2. Step 2: Apply lifting state up

   Move temperature state to their common parent and pass it plus update functions down as props.

3. Step 3: Avoid incorrect approaches

   Separate states cause inconsistency; global variables break React's data flow.

4. Final Answer:

   Move the temperature state to their common parent and pass value and update functions as props -> Option A

5. Quick Check:

   Lift shared state to parent for syncing siblings [OK]

Hint: Parent holds shared state; siblings get props and update functions [OK]

Common Mistakes:

• Keeping separate states causing out-of-sync inputs
• Trying to share state via global variables
• Passing state only to one sibling