Direct exchange in RabbitMQ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a direct exchange named 'logs'.

RabbitMQ

channel.exchange_declare(exchange='logs', exchange_type='[1]')

Drag options to blanks, or click blank then click option'

Adirect

Btopic

Cfanout

Dheaders

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'fanout' instead of 'direct' will broadcast messages to all queues.

Using 'topic' requires pattern matching, not exact routing keys.

The direct exchange type routes messages with a specific routing key to queues bound with that key.

2fill in blank

medium

Complete the code to bind the queue 'error_logs' to the exchange 'logs' with routing key 'error'.

RabbitMQ

channel.queue_bind(queue='error_logs', exchange='logs', routing_key='[1]')

Drag options to blanks, or click blank then click option'

Adebug

Berror

Cwarning

Dinfo

Attempts:

3 left

💡 Hint

Common Mistakes

Using a routing key that does not match the message's routing key will prevent message delivery.

Binding to the wrong exchange name will cause errors.

Binding with routing key 'error' ensures that messages sent with this key are routed to the 'error_logs' queue.

3fill in blank

hard

Fix the error in the code to publish a message with routing key 'info' to the 'logs' exchange.

RabbitMQ

channel.basic_publish(exchange='logs', routing_key='[1]', body='System started')

Drag options to blanks, or click blank then click option'

Ainfo

Berror

Cwarning

Dstart

Attempts:

3 left

💡 Hint

Common Mistakes

Using a routing key that does not match any queue bindings results in message loss.

Misspelling the routing key causes routing failures.

The routing key must match the intended message type, here 'info' to route correctly.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps routing keys to their message counts only if the count is greater than 5.

RabbitMQ

{key: counts[1] for key in counts if counts[key][2] 5}

Drag options to blanks, or click blank then click option'

A.get(key, 0)

B<

C>

D[]

Attempts:

3 left

💡 Hint

Common Mistakes

Using [] instead of .get() can cause errors if key is missing.

Using '<' will filter the wrong keys.

The comprehension uses counts.get(key, 0) to safely get counts and filters keys with counts greater than 5.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase routing keys to their counts only if count is greater than 10.

RabbitMQ

{ [1]: [2] for [3] in counts if counts[[3]] > 10 }

Drag options to blanks, or click blank then click option'

Akey.upper()

Bcounts[key]

Ckey

Dcounts.get(key, 0)

Attempts:

3 left

💡 Hint

Common Mistakes

Using counts.get(key, 0) is safe but unnecessary if keys exist.

Using the wrong variable name in the loop causes errors.

The comprehension maps uppercase keys to their counts, iterating over keys and filtering counts greater than 10.