Challenge - 5 Problems
Delimiter Mastery in read.table
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❓ Predict Output
intermediate2:00remaining
Output of read.table with comma delimiter
What is the output of the following R code when reading a CSV string with read.table using comma as delimiter?
R Programming
text <- "name,age,score\nAlice,30,85\nBob,25,90" data <- read.table(text = text, sep = ",", header = TRUE) print(data)
Attempts:
2 left
💡 Hint
Check the separator and header arguments in read.table.
✗ Incorrect
Using sep="," and header=TRUE correctly reads the CSV data into a data frame with columns name, age, and score.
❓ Predict Output
intermediate2:00remaining
Effect of wrong delimiter in read.table
What will be the output of this R code when reading a tab-separated string but using comma as delimiter?
R Programming
text <- "name\tage\tscore\nAlice\t30\t85\nBob\t25\t90" data <- read.table(text = text, sep = ",", header = TRUE) print(data)
Attempts:
2 left
💡 Hint
What happens if the separator does not match the actual delimiter in the data?
✗ Incorrect
Since sep="," does not match the tab characters, the entire line is read as one column using the first line as the column name "name\tage\tscore".
🧠 Conceptual
advanced1:30remaining
Understanding read.table default delimiter
Which delimiter does read.table use by default if sep is not specified?
Attempts:
2 left
💡 Hint
Think about how read.table handles spaces and tabs by default.
✗ Incorrect
By default, read.table treats any whitespace (spaces or tabs) as delimiter if sep is not set.
❓ Predict Output
advanced2:00remaining
Reading data with multiple delimiters
What will be the output of this R code that tries to read data with mixed delimiters using read.table?
R Programming
text <- "name;age,score\nAlice;30,85\nBob;25,90" data <- read.table(text = text, sep = ";", header = TRUE) print(data)
Attempts:
2 left
💡 Hint
What happens when sep matches only part of the delimiter pattern?
✗ Incorrect
Using sep=";" splits only on semicolon, so the second column contains the string with comma inside.
❓ Predict Output
expert2:30remaining
Handling missing values with read.table and delimiters
Given this R code reading data with missing values represented by empty fields, what is the output?
R Programming
text <- "name,age,score\nAlice,30,\nBob,,90" data <- read.table(text = text, sep = ",", header = TRUE, na.strings = "") print(data)
Attempts:
2 left
💡 Hint
How does na.strings argument affect empty fields?
✗ Incorrect
Setting na.strings to empty string converts empty fields to NA values in the data frame.