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mutate() for new columns in R Programming - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add a new column 'total' as the sum of 'x' and 'y'.

R Programming
library(dplyr)
data <- tibble(x = 1:3, y = 4:6)
data <- data %>% mutate(total = x [1] y)
Drag options to blanks, or click blank then click option'
A/
B-
C*
D+
Attempts:
3 left
💡 Hint
Common Mistakes
Using subtraction or multiplication instead of addition.
Forgetting to use mutate() to add a new column.
2fill in blank
medium

Complete the code to create a new column 'ratio' as 'x' divided by 'y'.

R Programming
library(dplyr)
data <- tibble(x = 10:12, y = 2:4)
data <- data %>% mutate(ratio = x [1] y)
Drag options to blanks, or click blank then click option'
A/
B+
C*
D-
Attempts:
3 left
💡 Hint
Common Mistakes
Using multiplication or addition instead of division.
Mixing up the order of operands.
3fill in blank
hard

Fix the error in the code to correctly add a new column 'diff' as the difference between 'a' and 'b'.

R Programming
library(dplyr)
data <- tibble(a = 5:7, b = 3:5)
data <- data %>% mutate(diff = a [1] b)
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using addition or multiplication instead of subtraction.
Swapping the order of operands.
4fill in blank
hard

Fill both blanks to create a new column 'score' as the product of 'm' and 'n' plus 10.

R Programming
library(dplyr)
data <- tibble(m = 2:4, n = 5:7)
data <- data %>% mutate(score = m [1] n [2] 10)
Drag options to blanks, or click blank then click option'
A*
B+
C-
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using addition before multiplication without parentheses.
Using subtraction or division instead of addition.
5fill in blank
hard

Fill all three blanks to create a new column 'result' as the uppercase of 'name', length of 'name', and check if length is greater than 4.

R Programming
library(dplyr)
data <- tibble(name = c('Anna', 'Brian', 'Clara'))
data <- data %>% mutate(result = list([1], [2], [3]))
Drag options to blanks, or click blank then click option'
Atoupper(name)
Bnchar(name)
Cnchar(name) > 4
Dtolower(name)
Attempts:
3 left
💡 Hint
Common Mistakes
Using tolower() instead of toupper().
Forgetting to compare length with a number.

Practice

(1/5)
1. What does the mutate() function do in R's dplyr package?
easy
A. It sorts the data frame by a column.
B. It deletes rows from a data frame.
C. It merges two data frames together.
D. It adds new columns or modifies existing ones in a data frame.

Solution

  1. Step 1: Understand the purpose of mutate()

    The mutate() function is designed to add new columns or change existing columns in a data frame.
  2. Step 2: Compare with other functions

    Deleting rows is done by filter(), sorting by arrange(), and merging by join functions, not mutate().
  3. Final Answer:

    It adds new columns or modifies existing ones in a data frame. -> Option D
  4. Quick Check:

    mutate() = add/change columns [OK]
Hint: mutate() changes or adds columns, not rows or merges [OK]
Common Mistakes:
  • Confusing mutate() with filter() for rows
  • Thinking mutate() merges data frames
  • Assuming mutate() sorts data
2. Which of the following is the correct syntax to add a new column total as the sum of columns a and b using mutate()?
easy
A. mutate(df, total = a + b)
B. mutate(df, total <- a + b)
C. mutate(df, total = sum(a, b))
D. mutate(df, total = a & b)

Solution

  1. Step 1: Check assignment inside mutate()

    Inside mutate(), new columns are created with =, not with assignment operator <-.
  2. Step 2: Understand how to sum columns element-wise

    To add columns element-wise, use a + b. Using sum(a, b) sums all values together, not element-wise. a & b is a logical AND, not addition.
  3. Final Answer:

    mutate(df, total = a + b) -> Option A
  4. Quick Check:

    Use = and + for element-wise sum [OK]
Hint: Use = and + inside mutate() for new column sums [OK]
Common Mistakes:
  • Using <- instead of = inside mutate()
  • Using sum() instead of + for element-wise addition
  • Using & instead of + for addition
3. Given the data frame df <- data.frame(x = 1:3, y = 4:6), what will be the result of mutate(df, z = x * y)?
medium
A. A data frame with columns x, y, and z where z is the product of x and y.
B. A data frame with columns x and y only, no new column added.
C. An error because mutate() cannot multiply columns.
D. A data frame with column z only containing the product values.

Solution

  1. Step 1: Understand mutate() behavior

    mutate() adds new columns without removing existing ones unless explicitly overwritten.
  2. Step 2: Calculate new column values

    For each row, z = x * y means multiplying corresponding elements: 1*4=4, 2*5=10, 3*6=18.
  3. Final Answer:

    A data frame with columns x, y, and z where z is the product of x and y. -> Option A
  4. Quick Check:

    mutate() adds z = x * y element-wise [OK]
Hint: mutate() keeps old columns and adds new ones [OK]
Common Mistakes:
  • Expecting mutate() to remove old columns
  • Thinking mutate() cannot do arithmetic
  • Assuming new column replaces all columns
4. What is wrong with this code snippet?
df <- data.frame(a = 1:3, b = 4:6)
df %>% mutate(c = a + d)
medium
A. The syntax of mutate() is incorrect; it needs a comma after c.
B. Column d does not exist in df, causing an error.
C. You cannot use the pipe operator %>% with mutate().
D. The code will run but c will be filled with NA values.

Solution

  1. Step 1: Check column names in data frame

    The data frame df has columns a and b, but no column named d.
  2. Step 2: Understand mutate() behavior with missing columns

    Trying to use a non-existent column d inside mutate() causes an error because R cannot find it.
  3. Final Answer:

    Column d does not exist in df, causing an error. -> Option B
  4. Quick Check:

    Using unknown columns in mutate() causes error [OK]
Hint: Check all columns exist before using in mutate() [OK]
Common Mistakes:
  • Assuming mutate() creates missing columns automatically
  • Thinking pipe operator %>% is invalid here
  • Believing syntax error due to missing comma
5. You have a data frame df with columns score1 and score2. You want to add a new column average that is the average of these two scores, but only if both scores are greater than 0; otherwise, average should be NA. Which mutate() code correctly does this?
hard
A. mutate(df, average = (score1 + score2) / 2)
B. mutate(df, average = ifelse(score1 > 0 | score2 > 0, (score1 + score2) / 2, NA))
C. mutate(df, average = ifelse(score1 > 0 & score2 > 0, (score1 + score2) / 2, NA))
D. mutate(df, average = ifelse(score1 & score2, (score1 + score2) / 2, NA))

Solution

  1. Step 1: Use ifelse() with correct condition

    The condition requires both score1 and score2 to be greater than 0, so use vectorized & inside ifelse().
  2. Step 2: Calculate average or assign NA

    If condition is true, calculate average as (score1 + score2) / 2, else assign NA.
  3. Final Answer:

    mutate(df, average = ifelse(score1 > 0 & score2 > 0, (score1 + score2) / 2, NA)) -> Option C
  4. Quick Check:

    Use ifelse() with & for both conditions [OK]
Hint: Use ifelse() with & to check both conditions [OK]
Common Mistakes:
  • Using | instead of & to require both conditions
  • Omitting ifelse() and always calculating average
  • Using score1 & score2 without comparison
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10 questions~5 mineasy hard