What is the output of the following R code that merges two data frames with duplicate keys using merge()?
df1 <- data.frame(id = c(1, 2, 2, 3), value1 = c('A', 'B', 'C', 'D')) df2 <- data.frame(id = c(2, 2, 3, 4), value2 = c('X', 'Y', 'Z', 'W')) result <- merge(df1, df2, by = 'id') print(result)
Remember that merge() with default settings performs an inner join and creates all combinations of matching keys.
The merge() function by default performs an inner join. Since id=2 appears twice in both data frames, it creates all combinations (2x2=4 rows) for that key. The id=3 row matches once. Keys not present in both data frames are excluded.
What will be the output of this R code that performs a left join using merge()?
df1 <- data.frame(id = c(1, 2, 3), value1 = c('A', 'B', 'C')) df2 <- data.frame(id = c(2, 3, 4), value2 = c('X', 'Y', 'Z')) result <- merge(df1, df2, by = 'id', all.x = TRUE) print(result)
Check which keys are in df1 and how all.x = TRUE affects the join.
Using all.x = TRUE keeps all rows from df1. For id=1, there is no match in df2, so value2 is NA. Rows with id=4 in df2 are excluded.
What error does this R code produce?
df1 <- data.frame(id = 1:3, val = c('A', 'B', 'C')) df2 <- data.frame(id = 2:4, val = c('X', 'Y', 'Z')) result <- merge(df1, df2, by.x = 'id', by.y = 'ID') print(result)
Check the exact column names in both data frames and the by.x and by.y arguments.
The column ID (uppercase) does not exist in df2. The correct column name is id (lowercase). This causes an error.
What is the output of this R code performing a full outer join?
df1 <- data.frame(id = c(1, 2, 3), val1 = c('A', 'B', 'C')) df2 <- data.frame(id = c(2, 3, 4), val2 = c('X', 'Y', 'Z')) result <- merge(df1, df2, by = 'id', all = TRUE) print(result)
Remember that all = TRUE keeps all rows from both data frames.
The full outer join includes all keys from both data frames. Missing values are filled with NA. So id=1 has val2=NA and id=4 has val1=NA.
Given these data frames, how many rows will the result have after merging by id and group?
df1 <- data.frame(id = c(1,1,2), group = c('A','B','A'), val1 = c(10,20,30))
df2 <- data.frame(id = c(1,1,2,2), group = c('A','A','A','B'), val2 = c(100,200,300,400))
result <- merge(df1, df2, by = c('id', 'group'))Count matching pairs of id and group in both data frames and consider duplicates.
The matching keys are:
- (1, A): df1 has 1 row, df2 has 2 rows → 1*2=2 rows
- (1, B): df1 has 1 row, df2 has 0 rows → no match
- (2, A): df1 has 1 row, df2 has 1 row → 1 row
- (2, B): df1 has 0 rows, df2 has 1 row → no match
Total rows = 2 + 1 = 3 rows.
But since (1, B) and (2, B) do not match in both, they are excluded.