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R Programmingprogramming~15 mins

Factor levels in R Programming - Mini Project: Build & Apply

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Factor levels
📖 Scenario: You are working with survey data where people's favorite fruits are recorded as text. To analyze this data properly, you need to convert the fruit names into a factor with specific levels.
🎯 Goal: Create a factor variable from a character vector of fruits with specified levels, so the data is ready for analysis.
📋 What You'll Learn
Create a character vector called fruits with the values "apple", "banana", "cherry", "banana", "apple"
Create a vector called fruit_levels with the values "apple", "banana", "cherry", "date"
Create a factor called fruit_factor from fruits using fruit_levels as the levels
Print the fruit_factor to show the factor with levels
💡 Why This Matters
🌍 Real World
Factors are used in R to handle categorical data like survey answers, product categories, or any group labels. Setting levels helps control the order and possible values.
💼 Career
Data analysts and statisticians use factors to prepare data for analysis and visualization, ensuring categories are handled correctly.
Progress0 / 4 steps
1
Create the character vector of fruits
Create a character vector called fruits with these exact values: "apple", "banana", "cherry", "banana", "apple"
R Programming
Hint

Use the c() function to combine the fruit names into a vector.

2
Create the vector of factor levels
Create a character vector called fruit_levels with these exact values: "apple", "banana", "cherry", "date"
R Programming
Hint

Use c() again to list the levels in the order you want.

3
Create the factor with specified levels
Create a factor called fruit_factor from the vector fruits using the levels from fruit_levels
R Programming
Hint

Use the factor() function with the levels argument.

4
Print the factor to see the levels
Print the variable fruit_factor to display the factor with its levels
R Programming
Hint

Use print(fruit_factor) to show the factor and its levels.

Practice

(1/5)
1. What does the levels() function do when applied to a factor in R?
easy
A. It changes the factor to a character vector.
B. It converts the factor to numeric values.
C. It shows the categories (levels) of the factor variable.
D. It removes unused levels from the factor.

Solution

  1. Step 1: Understand the purpose of levels()

    The levels() function in R returns the categories or labels assigned to a factor variable.
  2. Step 2: Differentiate from other functions

    Functions like as.numeric() convert factors to numbers, and droplevels() removes unused levels, but levels() only shows the current levels.
  3. Final Answer:

    It shows the categories (levels) of the factor variable. -> Option C
  4. Quick Check:

    levels() = shows categories [OK]
Hint: Remember: levels() lists categories, not changes data type [OK]
Common Mistakes:
  • Confusing levels() with as.numeric()
  • Thinking levels() removes unused categories
  • Assuming levels() converts factor to character
2. Which of the following is the correct way to create a factor with levels ordered as "Low", "Medium", "High" in R?
easy
A. factor(c("Low", "High", "Medium"), levels = c("Low", "Medium", "High"))
B. factor(c("Low", "High", "Medium"), levels = c("High", "Medium", "Low"))
C. factor(c("Low", "High", "Medium"))
D. factor(c("Low", "High", "Medium"), ordered = FALSE)

Solution

  1. Step 1: Understand factor creation with levels

    To set a specific order of categories, use the levels argument with the desired order.
  2. Step 2: Check the options

    factor(c("Low", "High", "Medium"), levels = c("Low", "Medium", "High")) sets levels as "Low", "Medium", "High" which matches the required order. factor(c("Low", "High", "Medium"), levels = c("High", "Medium", "Low")) reverses the order, C uses default alphabetical order, and D does not specify levels.
  3. Final Answer:

    factor(c("Low", "High", "Medium"), levels = c("Low", "Medium", "High")) -> Option A
  4. Quick Check:

    levels argument sets order [OK]
Hint: Use levels= to set order, not just values [OK]
Common Mistakes:
  • Not specifying levels leads to alphabetical order
  • Setting levels in wrong order
  • Ignoring levels argument
3. What will be the output of the following R code?
f <- factor(c("apple", "banana", "apple", "cherry"), levels = c("banana", "apple", "cherry"))
levels(f)
medium
A. [1] "apple" "banana" "cherry"
B. [1] "banana" "apple" "cherry"
C. [1] "apple" "cherry" "banana"
D. [1] "banana" "cherry" "apple"

Solution

  1. Step 1: Check the levels argument in factor()

    The factor is created with levels explicitly set as c("banana", "apple", "cherry"). This means the order of levels is exactly as given.
  2. Step 2: Output of levels(f)

    Calling levels(f) returns the levels in the order they were set, so it will print "banana", "apple", "cherry".
  3. Final Answer:

    [1] "banana" "apple" "cherry" -> Option B
  4. Quick Check:

    levels() returns set order [OK]
Hint: levels() shows levels in order set, not data order [OK]
Common Mistakes:
  • Assuming levels are sorted alphabetically by default
  • Confusing factor values with levels order
  • Expecting levels() to reorder automatically
4. Identify the error in the following R code snippet:
colors <- factor(c("red", "blue", "green"))
levels(colors) <- c("red", "blue")
levels(colors)
medium
A. The factor must be numeric before changing levels.
B. levels() cannot be assigned directly like this.
C. No error; code runs fine and shows updated levels.
D. Assigning fewer levels than existing causes mismatch error.

Solution

  1. Step 1: Understand levels assignment

    Assigning new levels directly replaces the old levels. The new levels vector must match the length of existing levels.
  2. Step 2: Check the code

    Original factor has 3 levels: "blue", "green", "red" (alphabetical order). The code tries to assign only 2 levels, causing a mismatch error.
  3. Final Answer:

    Assigning fewer levels than existing causes mismatch error. -> Option D
  4. Quick Check:

    levels replacement length must match [OK]
Hint: New levels vector length must equal old levels length [OK]
Common Mistakes:
  • Assigning fewer or more levels than original
  • Thinking levels() assignment always works
  • Ignoring alphabetical default order of levels
5. You have a factor f with levels c("small", "medium", "large"). You want to reorder the levels so that "large" comes first, then "small", then "medium". Which code correctly achieves this without changing the data values?
hard
A. f <- factor(f, levels = c("large", "small", "medium"))
B. levels(f) <- c("large", "small", "medium")
C. f <- factor(f, ordered = TRUE)
D. f <- factor(f, levels = sort(levels(f)))

Solution

  1. Step 1: Understand reordering factor levels

    To reorder levels without changing data, recreate the factor with the new levels order using the levels argument.
  2. Step 2: Analyze options

    f <- factor(f, levels = c("large", "small", "medium")) correctly sets new levels order. levels(f) <- c("large", "small", "medium") tries to assign levels directly, which can cause errors if lengths mismatch. f <- factor(f, ordered = TRUE) only makes factor ordered but does not reorder levels. f <- factor(f, levels = sort(levels(f))) sorts levels alphabetically, not custom order.
  3. Final Answer:

    f <- factor(f, levels = c("large", "small", "medium")) -> Option A
  4. Quick Check:

    Recreate factor with new levels order [OK]
Hint: Use factor() with levels= to reorder levels safely [OK]
Common Mistakes:
  • Assigning levels vector directly causing errors
  • Using ordered=TRUE without changing levels
  • Sorting levels instead of custom order
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