[Solved] Find the bug in this code snippet:with open('output.txt', 'w') as f: f.write(12345) — Ans: write() requires a string, not an integer. | Python

Python - File Handling Fundamentals

Find the bug in this code snippet:

with open('output.txt', 'w') as f:
    f.write(12345)

AMissing file close statement.

BFile mode 'w' cannot be used with write().

Cwrite() requires a string, not an integer.

Dopen() needs a second argument for encoding.

Step-by-Step Solution

Solution:

Step 1: Check argument type for write()
write() expects a string, but 12345 is an integer.
Step 2: Other points
'w' mode is correct, with block auto-closes file, encoding optional.
Final Answer:
write() requires a string, not an integer. -> Option C
Quick Check:
write() argument must be string [OK]

Quick Trick: Convert non-strings to str() before writing [OK]

Common Mistakes:

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