[Solved] What will be the output of this code?class Count: def __init__(self, limit): self.limit = limit self.num = 0 def __iter__(self): return self def __next__(self): if self.num | Python

Python - Magic Methods and Operator Overloading

What will be the output of this code?

class Count:
    def __init__(self, limit):
        self.limit = limit
        self.num = 0
    def __iter__(self):
        return self
    def __next__(self):
        if self.num < self.limit:
            self.num += 1
            return self.num
        else:
            raise StopIteration

for i in Count(3):
    print(i, end=' ')

AError: StopIteration not handled

B0 1 2

C1 2 3 4

D1 2 3

Step-by-Step Solution

Solution:

Step 1: Understand the iterator behavior
The Count class starts num at 0 and returns num+1 until it reaches limit 3.
Step 2: Trace the loop output
Loop prints 1, 2, 3 then raises StopIteration to end loop.
Final Answer:
1 2 3 -> Option D
Quick Check:
Count(3) yields 1 to 3 [OK]

Quick Trick: StopIteration ends loop; count from 1 to limit [OK]

Common Mistakes:

Starting count from 0 instead of 1
Expecting 4 as output
Thinking StopIteration causes error

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What will be the output of this code?

Step 1: Understand the iterator behavior

Step 2: Trace the loop output

Final Answer:

Quick Check:

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