[Solved] What will be the output of this code?class Context: def __enter__(self): print('Enter') return 10 def __exit__(self, exc_type, exc_val, exc_tb): print('Exit') with Context() as value: print(value * 2) | Python

Python - Context Managers

What will be the output of this code?

class Context:
    def __enter__(self):
        print('Enter')
        return 10
    def __exit__(self, exc_type, exc_val, exc_tb):
        print('Exit')

with Context() as value:
    print(value * 2)

AEnter 20 Exit

B20 Enter Exit

CEnter Exit 20

DExit Enter 20

Step-by-Step Solution

Solution:

Step 1: Follow __enter__ execution
On entering the with block, __enter__ prints 'Enter' and returns 10, assigned to value.
Step 2: Execute block and __exit__
The block prints 10 * 2 = 20. After block ends, __exit__ prints 'Exit'.
Final Answer:
Enter 20 Exit -> Option A
Quick Check:
Order: __enter__, block, __exit__ [OK]

Quick Trick: Return value from __enter__ is assigned inside with [OK]

Common Mistakes:

Printing value before __enter__
Mixing order of prints

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What will be the output of this code?

Step 1: Follow enter execution

Step 2: Execute block and exit

Final Answer:

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What will be the output of this code?

Step 1: Follow __enter__ execution

Step 2: Execute block and __exit__

Final Answer:

Quick Check:

Want More Practice?

Step 1: Follow enter execution

Step 2: Execute block and exit