[Solved] What is the output of this code?class A: def first(self): print('First') self.second() def second(self): print('Second') obj = A() obj.first() | Python

Python - Methods and Behavior Definition

What is the output of this code?

class A:
    def first(self):
        print('First')
        self.second()
    def second(self):
        print('Second')

obj = A()
obj.first()

ASecond

BSecond\nFirst

CFirst\nSecond

DFirst

Step-by-Step Solution

Solution:

Step 1: Trace method calls
Calling obj.first() prints 'First' then calls self.second(), which prints 'Second'.
Step 2: Determine output order
Output is 'First' then 'Second' on separate lines.
Final Answer:
First\nSecond -> Option C
Quick Check:
Method calls run in order called [OK]

Quick Trick: Follow method calls step-by-step to find output order [OK]

Common Mistakes:

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